Question

This is a matlab HW that I need the code for, if someone could help me figure this out it would be appreciated.

The value of t can be estimated from the following equation: in your script file, estimate the value of π for any number of terms. You must ask the user for the desired number of terms and calculate the absolute error/difference between your calculation and the built-in MATLAB value ofpi. Display your results with the following message (including the asterisks) where II is the number of terms used to calculate π, F. FFFFFFFFFF is your final result printed out with %f with 10 digits past the decimal point, and E. EEEEEEEE is the absolute error/difference between your calculation and pi printed out with &E with 8 digits past the decimal point. rwer %; 鼎鼎鼎鼎鼎鼎鼎 For II terms the estimated value of PI -F. FFFFFFFFFF with an absolute difference of E.EEEEEEEE with pi in MATLAB You may test your program with 5, 10, and 40 terms. HINT: Use a for loop to calculate the product above. Note that the numerator of term 1 is 2+0 and numerator of term 2 is /2 +numerator of term 1. This pattern is repeated for the rest of terms. Also, note that every numerator is divided by 2. The final value of pi can then be calculated from the completed product. It is strongly recommended that you use the in-class activities and lecture notes as a model for how to write your code. The following are infinite series representations of the function n+ 1 f(x) (1 + x) ex- n=0 in your script file, estimate f(x) using the infinite series for a given value(s) of X. You must prompt the user to enter the value(s) of x; x may be entered as a scalar, vector or matrix. Use the factorial function to calculate n!. You must estimate f(x) for each value in x using a while loop that computes the sum until the absolute value of the nth term is less than a user defined tolerance, i.e. your program must prompt the user for a tolerance, or a maximum number of 50 iterations has been reached If the user enters in a tolerance outside of the range [0, 10E-2], you must print out the following message and re-ask the user repeatedly until they enter in an appropriate tolerance value Invalid entry, please re-enter a tolerance If the maximum number of iterations was reached for a given x value, the following message must be displayed The allowable number of iterations has been exceeded. If x is a scalar, display the final result with the following message where XX indicates where numbers should be placed. You may use the isscalar function to determine if x is a scalar. In XX iterations, the final result of (1 + X.xx) *exp (X. XX) is: XX.XX If x is an array, display the final result with the following message where x.xxx indicates the values stored inside the final result. Final result of (1 x) *exp (x) is:

Answer 1

IF YOU HAVE ANY DOUBTS COMMENT BELOW I WILL BE THERE TO HELP YOU

ANSWER:

CODE:

format long
inp2 = input('Enter the number of terms : ','s');
m = str2double(inp2);
t = 0;
s = 1;

for i = 1:m
for j = 1:i
t = sqrt(2 + t);
end
s = s * (t / 2);
t = 0;
end
s = 2 / s;
disp(s);

>>genPi Enter the number of terms 5 3.140331156954753 >>genPi Enter the number of terms 10 3.141591421511200 >>genPi Enter the number of terms 40 3.141592653589794

THANKS

OR

CODE:

clc
clear all
n=input('enter the valus of terms you need i.e n :'); % getting input for number of function from opeartor

for i=2:n
x(1)=(sqrt(2)); %defining first term without condsidering 2
x(i)=(sqrt(2+x(i-1))); %getting all numerator for (2/pi) as subject of equation
end
for i=1:n
x(i)=(x(i))/2;   
y(i)=(1/x(i)); %here we shall make pi as subject of our equation so we shall get eqm for (pi/2)
end
for i=1:n %loop for product of all numbers
if i==1
diff_pi(1)=y(1);
else
diff_pi(i)=y(i)*diff_pi(i-1);
end
end
absdiff= (pi)-2*diff_pi(n); %required answer
Diff_pi=2*diff_pi(n); %required answer   
fprintf('***************************************************\n');
fprintf('for %1f terms the estimeted value of PI = %1.10f with\n',n,Diff_pi);
fprintf('an absolute differnce of %1.8f with pi in MATLAB\n',absdiff);