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1. 1i3 points | Previous Answers My Notee Aek Your Teacher 11 6.3.001 The given differential equation is a model of an undamp

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Answer #1

MATLAB Code:

close all
clear
clc

% x'' = -x^3
% x' = x1
% x1' = -x^3

[t, x] = ode45(@vdp, [0 20], [1; 1]);
figure, hold on
grid on
plot(t, x(:,1))
[t, x] = ode45(@vdp, [0 20], [1/2; -1]);
plot(t, x(:,1))
title('Solution Curves'), xlabel('t'), ylabel('x(t)')
hold off

function dxdt = vdp(~, x)
% x(1) => x, x(2) => x1
dxdt = [ x(2);
-x(1)^3];
end

Plot:

Solution Curves X: 6.182 Y: 0510

For first graph (first set of initial conditions): Period is 5.6 approximately.

For second graph (second set of initial conditions): Period is 6.2 approximately.

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