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Vibration and Rotation Exercise 4 Part E ReviewI Constants Periodic Table Assume that for H5Cl molecule the rotational quantu

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Answer #1

Part E:

The period of vibration, Tvib, can be calculated from the following formula:

2π

Reduced mass: mHMcu 1.0078 * 34.9688 mH + Mc 1.0078 +34.9688

Given, k=516 Nm-1=516 kg sec-2.

Therefore, Tvib=2*3.14159/(516/1.627*10-27)1/2 sec=1.12*10-14 sec.

Part F:

1-μ.r2-1.627 * 10-27 * 127,52 kgpm2-1.627 * 10-51 * 127,52 kgm2 21.5 kap 121. kgm

From \frac{1}{2}I \omega^2=j(j+1)\frac{\hbar^2}{2 I} , one has

\omega=\sqrt{j(j+1)}\frac{\hbar}{ I}, where j=9.

Therefore, -2.65 10-4sec.

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