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4. 8/20 points lPrevious Answers SerCP10 22.P.004 (a) Calculate the wavelength of light in vacuum that has a frequency of 5.1

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Answer #1

A)

Wavelength, lambda = (3 x 10^8)/(5.1 x 10^15) = 0.588 nm

B)

Wavelength, lambda = (3 x 10^8)/(5.1 x 10^15 x 1.5865) = 0.371 nm

C)

Energy, E = hf = (6.63 x 10^-34)(5.1 x 10^15) = 3.38 x 10^-18/1.6 x 10^-19 = 21.13 eV

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