Question

2. Figure 5.15 (on page 170 of Schroeder book) shows that at a fixed temperature, how to identify the critical pressure Pc when V is constant over this pressure range. However, we know that diamond is harder tharn graphite: In other words, graphite is more compressible than diamond. (Recall the isothermal compress- ibility RT- , the same as defined in the previous HW9.) ility KT 1%,x® the same as defined in thand (a) If we consider the finite compressibility, how do you expect the critical pressure changes, higher or lower T,N than predicted in Fig. 5.15? Explain your answer briefly (b) The compressibility of graphite,3x 10-6 bar1 and that of diamond is about 10 times smaller, for which we justify ignoring the compressibility of diamond. Using this information, give more detailed estimation of Po at which diamond becomes more stable than graphite at room temperature.

Answer 1

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