20. Ethylenediaminetetraacetate (EDTA4-) is used as a complexing agent in chemical analysis. Solutions of EDTA4- are used to treat heavy metal poisoning by removing the heavy metal in the form of a soluble complex ion. The complex [Pb(EDTA]2- has Kf = 1.1 x 1018.
a. Calculate the concentration of Pb2+ in a saturated solution of Pb(OH)2, Ksp = 1.2 x 10-15.
b. Calculate the concentration of Pb2+ in a saturated solution of Pb(OH)2 buffered at pH 13.00
c. Calculate the concentration of Pb2+ in a 1.0 L solution containing 0.050 M Na4EDTA with 0.010 mole Pb(NO3)2 added (assume negligible volume change due to addition of this solid).
d. Consider a solution with 0.010 mole Pb(NO3)2 added to 1.0 L of an aqueous solution buffered at pH = 13.00 and also containing 0.050 M Na4EDTA. Does Pb(OH)2 precipitate from this solution?
20. Ethylenediaminetetraacetate (EDTA4-) is used as a complexing agent in chemical analysis. Solu...
The Kf for the formation of the complex ion between Pb2+ and EDTA4− is 1.0 × 1018 at 25° C. Pb2+ + EDTA4− ⇌ Pb(EDTA)2− Calculate the [ Pb2+ ] at equilibrium in a solution containing 2.50 × 10−3 M Pb2+ and 3.50 × 10−3 M EDTA4
In the presence of excess OH-, the Al3+(aq) ion forms a hydroxide complex ion, Al(OH)4-. Calculate the concentration of free Al3+ ion when 1.32×10-2 mol Al(NO3)3(s) is added to 1.00 L of solution in which [OH- ] is held constant (buffered at pH 13.00). For Al(OH)4-, Kf = 1.1×1033. [Al3+] = ?M
Calculate concentration of species in a solution containing a complex ion In the presence of excess OH, the Al3 (aq) ion forms a hydroxide complex ion, AIOH)4. Calculate the concentration of free Al3 ion when 1.46*102 mol Al(NO3)3(s) is added to 1.00 L of solution in which [OH-] is held constant (buffered at pH 12.60). For Al(OH)4, K?1.1x1033.
to answer number 28. you refer back to 24. but im stuck on it ans confused. 2NaC1 HOH c. + MgC12 + H2S04> Na2S04+2HCI d. Ca(OH)2+ Pb(NO3)2> Ca(NO3)2 + Pb(OH)2 3 parts) What is the H+ concentration and pH of a 0.20 M solution of hypochlorous acid, Ka 3.5 x 10*? (SHOW ALL STEPS FOR CR CONC. AND SOLVE FOR 22.pH ) 20. ICE CHART, sOLVE FOR 21 23. What is the hydroxide ion concentration and pH of a 0.10...
Calculate concentration of species in a solution containing a complex ion. Close Problem In the presence of excess OH-, the Al3+(aq) ion forms a hydroxide complex ion, Al(OH)4-. Calculate the concentration of free Al3+ ion when 1.21×10-2 mol Al(CH3COO)3(s) is added to 1.00 L of solution in which [OH- ] is held constant (buffered at pH 12.60). For Al(OH)4-, Kf = 1.1×1033. [Al3+] = M
Calculate concentration of species in a solution containing a complex ion. In the presence of excess OH^ -, the Al^ 3+ (aq) ion forms a hydroxide complex ion, Al(OH)^ -_4. Calculate the concentration of free Al^ 3+ ion when 1.64 times 10^-2 mol Al(CH_3COO)_3(s) is added to 1.00 L of solution in which [OH^ -] is held constant (buffered at pH 12.10). For Al(OH)_4^ -, K_f = 1.1 times 10^33.
Write the balanced chemical equation for each of the reactions. Include phases. When aqueous sodium hydroxide is added to a solution containing lead(II) nitrate, a solid precipitate forms. equation: 2 NaOH + Pb(NO3)2 + Pb(OH), + 2NaNO, However, when additional aqueous hydroxide is added, the precipitate redissolves, forming a soluble (Pb(OH),12- (aq) complex ion. equation: Pb(OH), +20H (Pb(OH) 2 -
In the presence of excess OH-, the Zn2+(aq) ion forms a hydroxide complex ion, Zn(OH)42-. Calculate the concentration of free Zn2+ ion when 1.57×10-2 mol Zn(NO3)2(s) is added to 1.00 L of solution in which [OH- ] is held constant (buffered at pH 12.20). For Zn(OH)42-, Kf = 4.6×1017. [Zn2+]=___M please explain
question 17 & 18 Q17. A 5.0 x 10-M solution of Mn is gradually made more basic by adding NaOH. At what pH will manganese(II) hydroxide begin to precipitate? For Mn(OH)2. Kip - 2.0 x 10-13 Q18. A solution is 0.010 M in each of Pb(NO3)2. Mn(NO3). and Zn(NO3)2. Solid NaOH is added until the pH of the solution is 8.50. Which of these three metal ion(s) will precipitate as a hydroxide? Salt KR Pb(OH)2 1.4 x 10-20 Mn(OH)2 Zn(OH)2...
Calculate the solubility of barium sulfate. BaSO4 in units of grams per liter. Ksp (BaSO4) = 1.1x10-10 solubility = AL The equilibrium concentration of chloride ion in a saturated lead chloride solution is M. In the presence of excess OH, the Ar+ (aq) ion forms a hydroxide complex ion. Al(OH)4 Calculate the concentration of free Ap+ ion when 1.56x10-mol Al(CH2C00)3(s) is added to 1.00 L of solution in which [OH-] is held constant (buffered at pH 12.10). For Al(OH)4, Ke=...