As per standard reduction potentials Cu2+ + 2e- -----------> Cu ; Eo = 0.34 V,
Cu2+ + e- -----------> Cu+ , Eo = 0.16 V,
Hg2+ + 2e- -----------> Hg ; Eo = 0.85 V,
Answer a)
Equation involved is Hg2+ + 2Cu+ -----------> Hg + 2Cu2+
Eo = 0.85 - 0.16 = 0.69 V
Correct statements are:
K > 1 (because Eo is positive, so K is also positive i.e more than 1)
delta Go < 0 (because Go = -nFEo, as Eo is positive, Go will be negative)
Incorrect statements are so, because
n = 1, (it is actually n = 2)
Eo < 0 (it is actually Eo > 0)
Reaction is reactant favored (because K > 1, reaction is product favored).
Answer 2
Equation involved is Cu2+ + Hg -----------> Cu + Hg2+
Eo = 0.34 - 0.85 = - 0.51 V
Correct statements are:
Eo < 0 (as calculated above)
n = 2
K < 1 (because Eo < 0, so log K will be negative and K < 1)
Incorrect statements are
delta Go < 0 (because Go = -nFEo, as Eo is negative, Go will be positive)
Reaction is product favored (because K < 1, reaction is reactant favored).
The answers can be predicted without considering reduction potential values by the fact that "Hg is less reactive than copper as per reactivity series"
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