a) The walls of the box are insulated. Since there is no heat
flow we do not expect any change in internal energy in free
expansion. That is there will be no change in temperature of the
ideal gas.
2. [4] Consider a box of volume V2 with a partition that separates a third of the box, Vi-V2 /3, ...
b) What is the change in
entropy of the gas, , as a
result of the sudden expansion?
please help me by doing all
the parts of this question, I really appreciate your help!
[18] Consider a box of volume V2 with a partition that separates a third of the box, V1 V2 /3, from the rest. Initially, V,contains N molecules of monatomic ideal gas at temperature ti, while the is empty. The walls of the box areL re well...
. (40 points) Consider an insulated container of volume V2. N idea gas molecules are initially confined within volume V, by a piston and the remaining volume V2 - Vi is in vacuum. Let T,, P1, E1, S, Al, Hi, G, be the temperature, pressure, energy, entropy, Helmholtz free energy, enthalpy, and Gibbs free energy of the ideal gas at this state, respectively V1 V2-V Using Sackur-Tetrode equation for the entropy of ideal gas where kB R/NA is Boltzmann's constant...
8. Initially, 1 mole of the real gas is contained in a thermally insulated piston-cylinder arrangement in an initial state (T1, P1, Vi ). 1 mole of the real gas that is expressed by the following equation of state under the investigation. Now, the gas is expanded so as to fill the final state of (T2, P2, V2 ). Suppose that any possible temperature dependence of Cy is negligibly small and the molar heat capacity is approximately equal to 2"...
VI/TI-V2/T2 2.) The volume of a gas is always equal to the volume of its (Ipt) 3.) What temperature unit must always be used for gas law problems? (1 pt)
A monatomic ideal gas is initially at volume, pressure, temperature (Vi, Pi, Ti). Consider two different paths for expansion. Path 1: The gas expands quasistatically and isothermally to (Va, Pz. T2) Path 2: First the gas expands quasistatically and adiabatically (V2, P.,T-),where you will calculate P T. Then the gas is heated quasistically at constant volume to (Va. P2 T1). a. Sketch both paths on a P-V diagram. b. Calculate the entropy change of the system along all three segments...
4. [After Reif Problem 5.1] When an ideal gas undergoes an adiabatic (thermally insu- lated) quasi-static expansion, its pressure and volume are related by p = constant. where γ = cp/cv is the ratio of heat capacities. If the gas expands from an initial volume Vi at temperature T to a final volume V2, calculate the final temperature T2 in terms of γ, Vi, Ti, and ½.
4. Consider a heat engine based on the Stirling cycle. Pressure Vs Volume V2 Steps 1-2 and 3-4 are at constant temperature (1-2 at temperature TH and 3-4 at temperature To, and steps 4-1 and 2-3 are at constant volume (2-3 at volume V2, and 4-1 at volume V) a) Determine expressions for the heat and work in each step. b) Calculate an expression for the efficiency e of this heat engine as a function of TH TC, V2, Vi,...
Initially, at a temperature T, and a molar volume vi, a van der Waals gas undergoes a change of state to the final temperature T2 and the molar volume V2. The van der Waals gas is characterized by the two parameters a and b (cf. Eq. (3.3)). a. Show that the change in molar entropy is As = c, In 72 + R In º2 = (3.62) 01 - 6 b. A volume of 1 dm is partitioned by a...
someone please help me with this. help me to solve
where i went wrong. and please show all steps and explain every
step.
a more clear picture
i uploaded the same picture i hope u can understand
italso these notes
11:47 00 in the made DU - . F -BUT Sez(-BUT") (P = BTV 7 ( 5 . lavity, energy, Gibbs I re-de the free energy quiz - Going over Quiz PV=const. Ideal Gas it 7=const BB p=constant srT3V =...
4. The pressure-volume diagram below shows a special reversible cycle called the Carnot cycle A mole of an ideal gas starts off in state 1 in contact with a large thermal reservoir at temperature Th. The gas then undergoes an isothermal expansion from Vi to V2. Upon reaching state 2, the gas container is removed from contact with the thermal reservoir and covered with thermal insulation. Next the gas is allowed to expand adiabatically from V2to Vs. Because the expansion...