1. The lumen output was determined for each of I = 3 different brands of lightbulbs having the same wattage, with J = 8 bulbs of each brand tested. The sums of squares were computed as SSE = 4775.1 and SSTr = 590.8. State the hypotheses of interest (including word definitions of parameters).
A) μi = true average lumen output for brand i bulbs H0: μ1 = μ2 = μ3 Ha: at least two μi's are unequal
B) μi = true average lumen output for brand i bulbs H0: μ1 ≠ μ2 ≠ μ3 Ha: at least two μi's are equal
C) μi = sample average lumen output for brand i bulbs H0: μ1 ≠ μ2 ≠ μ3 Ha: all three μi's are equal
D) μi = sample average lumen output for brand i bulbs H0: μ1 = μ2 = μ3 Ha: all three μi's are unequal
2. Use the F test of ANOVA (α = 0.05) to decide whether there are any differences in true average lumen outputs among the three brands for this type of bulb by obtaining as much information as possible about the P-value. (Round your answer to two decimal places.)
f = ?
3. What can be said about the P-value for the test? Select an answer
A)P-value > 0.100
B)0.050 < P-value < 0.100
C)0.010 < P-value < 0.050
D)0.001 < P-value < 0.010
E)P-value < 0.001
4. State the conclusion in the problem context.
A)Fail to reject H0. There are statistically significant differences in the lumen output.
B)Reject H0. There are statistically significant differences in the lumen output.
C)Reject H0. There are no statistically significant differences in the lumen output.
D)Fail to reject H0. There are no statistically significant differences in the lumen output.
Ans:
1)
H0: μ1 = μ2 = μ3
Ha: at least two μi's are unequal
2)
SS | df | MS | F | |
Treatments | 590.80 | 2 | 295.40 | 1.30 |
error | 4775.10 | 21 | 227.39 | |
Total | 5365.90 | 23 |
F=1.30
3)p-value=FDIST(1.30,2,21)=0.2938
P-value > 0.100
4)Fail to reject H0. There are no statistically significant differences in the lumen output.
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