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There are sparse quantities of atomic hydrogen in interstellar space, the details of whidh are important for studying star fo

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Answer #1

The given expression can be written as ,

  \Delta E_{IFS}=\frac{g_p h^4}{12 \pi^2m_e^2c^2 a_0^2}

where gp =5.59 is the gyro-magnetic ratio of proton and a0 is the Bohr radius. Inserting numerical values of the constants in the above expression, we obtain

\Delta E_{IFS}=\frac{5.59 \times (6.636 \times10^{-34} )^4}{12 \times (3.14)^2 \times (9.11 \times 10^{-31})^2 \times (3 \times 10^8)^2 \times (0.529 \times 10^{-10})^2}=9.4 \times 10^{-25} J

Frequency of the emitted photon in this transition is

\nu=\frac{\Delta E_{IFS}}{h}=\frac{9.4 \times 10^{-25}}{6.626 \times 10^{-34}}=1420 MHz

Hence wavelength of the emitted radiation is

\lambda=\frac{c}{\nu}=\frac{3 \times 10^8}{1420 \times 10^6}=21 cm

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