Question

Write condensed electron configurations for the following atoms and ions, using appropriate noble-gas core abbreviations. Put superscripted electron count numbers in parentheses. Examples: Fe = [Ar]4s(2)3d(6), Sn2+ = [Kr]4d(10)5s(2), S2- = [Ar]. (a) Ba2+ = [Xe]6s(0) Incorrect: Your answer is incorrect. (b) Ca2+ = [Ar] Correct: Your answer is correct. (c) Cu+ = Incorrect: Your answer is incorrect. (d) Ti2+ = [Ar]3d(2)4s(0) Incorrect: Your answer is incorrect. (e) Co = Incorrect: Your answer is incorrect.

Answer 1

Solution:-

Part a) Ba^2+ ion have same number of electrons as the Xenon atom.

Therefore the condensed electronic configuration for the Ba^2+ is as follows

Ba^2+ = [Xe]

Part b) Ca^2+ ion contains 18 electrons which are same as Argon therefore the condensed electronic configuration is as follows.

Ca^2+ = [Ar]

Part c) Cu^+ ion contains 28 electron

Cu^+ = [Ar]3d(10)

Part d) Ti^2+ ion contains 20 electrons therefore the electronic configuration is as follows

Ti^2+ = [Ar]3d(2)

Part e) Co atom contains 27 electron therefore the electronic configuration is as follows

Co= [Ar]3d(7)4s(2)