Question

WasteNot Recycling WasteNot Recycling picks up recyclables from homeowners in Boulder, Colorado. Neighborhoods subscribe to the service so that pickup is cost-effective. WasteNot provides special containers to subscribers for sorting recyclables: a blue container for paper products and a purple container for aluminum, plastic, and glass products. Subscribers place their recycling containers on the curb for biweekly pickup. Each recycling container is weighed before being emptied. WasteNot drivers carry handheld recording devices used to track each pickup. Subscribers receive quarterly profit-sharing checks based on their contributions. If WasteNot does not make a profit, subscribers are not paid for their recyclables. If WasteNot makes a profit, subscribers share in that profit. WasteNot has asked you to help develop a relational database that will effectively track subscribers, using the data downloaded from the drivers’ devices. WasteNot has provided you with a snapshot of two tables you need to create. The Customer table shown here holds static customer information such as name, address, and phone. The Customer Record table holds data about each recyclable pickup. Specifically, WasteNot needs you to:

Customer Table:

Customer ZIP Name Name Phone Pickup Wagoner Sam 5480 Alpine Street Boulder CO 80308 (303) 161- 05/25/2004 80308(303) 886-05/2

Customer Record Table

Customer ID Weight Other Srvc Date 11/22/2007 10/15/2007 1/7/2007 1/7/2007 11/22/2007 10/15/2007 11/22/2007 12/4/2007 10/15/2

1. Create a Microsoft Access database.

2. Create the tables, fields, data types, and primary key(s) for the database.

3. Create the relationship(s) needed between the tables.

After completing parts 1 through 3 of this assignment, you should also:

Add two additional customer records, one with your name and one with a friend's name.

Add an additional 14 records to the Customer Service record table. These records should indicate service dates in January and February of 2007. They should also be related to existing customers in the Customer table (including the customer record for you and your friend).

When you create the relationship between the 2 tables (i.e. part 4 of this problem), please be sure to check the checkbox for "Enforce Referential Integrity" as well as the checkboxes for "Cascade Update Related Fields" and "Cascade Delete Related records". If you do not check these boxes as specified you may come up with radically different answers to the questions.

You will now make some observations based on the following questions:

What happens when you try to enter a record into the Customer Service records table for which there is no corresponding record in the Customer table?

What happens when you try to delete a record from the Customer records table for which there is at least one corresponding record in the Customer Service records table?

What happens when you try to change the value of "Customer ID" in the Customer table for which there IS at least one corresponding record in the Customer Service Records table?

Show transcribed image text

Customer ZIP Name Name Phone Pickup Wagoner Sam 5480 Alpine Street Boulder CO 80308 (303) 161- 05/25/2004 80308(303) 886-05/25/2004 80308 (303) 562- 08/25/2005 80308(303) 792- 02/28/2004 80308 (303) 838- 06/02/2004 80308(303) 352- 07/17/2005 80308 (303) 555- 05/19/2005 80308(303) 815- 12/28/2004 80308 (303) 333- 07/19/2003 5545 Calahan 2140 Edgewood | Boulder | CO Avenue 6003 Lake James 701 Eastman Boulder CO Road 4499 Meadows Sara Pond Hill Drive Boulder CO 3646 20 Alto CO 114 Lexington Street Boulder 64 Monarch Shiela431 Phillips Lane Boulder CO 4847 1935 Snow Avenue Boulder CO 6731 482 Weston Avenue 80 Rivera Juan Boulder CO 2456 230 Southpark Circle 85 Williams Max Boulder CO
Customer ID Weight Other Srvc Date 11/22/2007 10/15/2007 1/7/2007 1/7/2007 11/22/2007 10/15/2007 11/22/2007 12/4/2007 10/15/2007 11/22/2007 10/15/2007 1/7/2007 11/22/2007 12/4/2007 Weight Paper 15 32 12 19 28 174 32 12 40 16 20 20 80 80 80 80 18 35 10 10 13 18 16 18
0 0
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Answer #1

Answer)

1. Create a Microsoft Access database.

We are going to create the customer database in access.

New Blank Database Blank Database Featured Online Templates o, Assets Contacts Issues Events Marketing projects Projects Sale

2. Create the tables, fields, data types, and primary key(s) for the database.

I have create the tables

Customer Field Name Data Type CustomerID LastName FirstName Street City State ZipCode Phone FirstPickup Number Text Text Text

E Customer Record Table Field Name Data Type ustomer ID Srvc_Date Weight_Paper Weight_Other Number Date/Time Number Number

3. Create the relationship(s) needed between the tables.

Now I create the relationship between the tables with "Enforce Referential Integrity" as well as the checkboxes for "Cascade Update Related Fields" and "Cascade Delete Related records".

Relationships Customer Customer Record Ta... CustomerID Customer ID Sryc Date Weight Paper Weight Other LastName FirstName St

Relationships Customer Customer Record Ta... CustomerID LastName FirstName Street City State ZipCode Customer ID Srvc Date We

What happens when you try to enter a record into the Customer Service records table for which there is no corresponding record in the Customer table?

When we try to insert a record in the customer service record table we will get error because corresponding record in the child table is not found.

Customer_Record_Table Customer-l- 1 Srvc-Date 22-Nov-07 -weight-Pap-weight Oth- 8 15 米 icrosoft Office Access You cannot add

What happens when you try to delete a record from the Customer records table for which there is at least one corresponding record in the Customer Service records table?

If we delete a record then all the corresponding records will be deleted

CustomerID.| LastName FirstName Street City State ▼ ZipCode Phone 米 icrosoft Office Access Relationships that specify casca

What happens when you try to change the value of "Customer ID" in the Customer table for which there IS at least one corresponding record in the Customer Service Records table?

If we change the value then the corresponding records value will also be changed.

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