Evaluate the integral cosh(z2) dx dy dz J0 J0Jy
The question is, evaluate the following integral. 1+x2+22 43. dy dx dz Jo Jo
The figure shows the region of integration for the integral. fx, y, z dy dz dx 0 Jo Rewrite this integral as an equivalent iterated integral in the five other orders. (Assume yx) 6x and z(x)-36-) x. f(x, y, 2) dy dx dz x, , z) dz dx dy f(x, y, z) dz dy dx f(x, y, z) dx dy dz fx, y, z) dx dy dz J0 Jo Jo f(x, y, z) dz dx dy 0 0 f(x, y,...
(1 point) Evaluate the integral. 16 16- S. 1 (a2y2z2)1/2 dy dz dx 16-r 0 (1 point) Evaluate the integral. 16 16- S. 1 (a2y2z2)1/2 dy dz dx 16-r 0
Evaluate the integral. 2 V4-y2 aproba o por con 2x+4y dz dx dy
Evaluate the iterated integral sin x dx dy. Jo Jy
16. o integrad [**** The triple da dy dz describes the solid pictured at right. Rewrite as an equivalent triple integral in the following orders (DO NOT EVALUATE): 31 (a) dy dz dx (b) du dz dy 2. 16-2 21. Given dy da, 16- (a) Sketch the region of integration and write an equivalent iterated integral in the order dx dy. (You do not need to evaluate it!) (b) Now write it as an equivalent iterated integral in polar coordinates....
(5,3,-2) Evaluate the integral y dx + x dy + 4 dz by finding parametric equations for the line segment from (2,1,5) to (5,3,-2) and evaluating the line integral of (2,1,5) F = yi + x3 + 4k along the segment. Since F is conservative, the integral is independent of the path. (5,3,-2) y dx + x dy + 4 dz= (2,1,5)
Do not evaluate, rewrite the integral using spherical coordinates 25-x² - y2 1 dz dx dy 05 NUS y=0 X-O Z=o
25 2 6 Evaluate the integral S SS 3 cos (x2) -dx dy dz by changing the order of integration in an appropriate way. 417 o o Зу