Question

6.39 Let vg represent the voltage across the current source in the circuit in Fig. 6.29. The reference for vg is posi- tive at the upper terminal of the current source. a) Find vg as a function of time when , = 16-16e-51 A. b) What is the initial value of vg? c) Find the expression for the power developed by d) How much power is the current source develop- e) Calculate the power dissipated in each resistor the current source. ing when t is infinite? when t is infinite. 4 H 5Ω 8H 20 Ω 16H ( i2 ) 60 Ω Figure 6.29 ▲ The circuit for Example 6.8. a KVL equation for each mesh where the current is unknown. Summing the voltages around the i1 mesh yields did 4 + 8u (ig-12 ) + 20(11-12) + 5(h-ig) = 0. dt dt 1'g

Answer 1

16--(16) 51 16H 60 t2 ther 16ft dut dt dlt 80%-août 16.d_c4-包+1..o. ● 80'1-aoçt16 dr (G-g) tädu.co-X.D.

(大上 L-Ci.) dt Heae dt o di よ Sto St し (a) . d t (a) ,

dlt dt dt dt ノグ dt dt dt ea つ4丝-8丝+4s (9-.ao6-ς&噜 8-(16-16, est) t) St dt dt -St -St-st dt dt -St

goj (80) e -St -5t t2(16) dig dlt dt st dt dt dlt -St