Question

120,121,122

120. Acompar y teeds to locate three depannat.(XYand Z) inde three anem cL. II, and IIIトof.tev facilay. They wa ominimie nerdparmencal tanspotation costs, which are especsed to be 5.50 per land per menar noved An analyst has prep red the Sollowwig ataces and tw ณ ices Dutanos (meters) Flows (leads par meek 2 110 140 If departments X.Yand Z were to be lcated in areas L.11l, and IIL respectively, what would be the otal is mters) loads e moved cach week? 4,000 4.900 C 7.000 9,000 Multiply the loads ooeveyed by the distance traveled 121. A conspany needs to locate three depamS X,Yand Z in the three s L. I1, and l)ofaneu load per meter meved An analye has prepared the following distances and ow matrices Distances (meters) Flows(eads per week 10 20 Z 110 140 What ane total wekly costs for the least costly process layou 52.800 D. 54,000 E $4 500 Multiply cach load meter by the cos per load mcter 122. A cempany needs to locale three depanms (X,Y and Z in the three aeas (. I1, and ll) of a new load per matier moved. An analyse has preparod the following distances and Bow matrices Ditances (meters) Flows eads per week 10 20 60 90 Z 110 140 How many least costly pracess layouts ane the

Answer 1

120. D. 8,000

Total cumulative distance = SUMPRODUCT of distance between pair of locations times Flows between departments

= Distance between I and II * Flows between (X and Y + Y and X)

+ Distance between I and III * Flows between (X and Z + Z and X)

+ Distance between II and III * Flows between (Y and Z + Z and X)

= 10*(60+40)

+ 20*(90+110)

+ 10*(160+140)

= 8,000

121. C. $ 3,500

To minimize the total cost, departments having the highest flows must be located closest to each other. Depts Y and Z have the highest flows of  300 (160+140), so they must located closest to each other.

Depts X and Z have the second highest flows of 200 (=90+110), so they must also be located closest to each other.

Which means Z must be located closest to X and Y. So Z must be in the middle of X and Y. Optimal layout is:

I	II	III
X	Z	Y

Cumulative load x distance = 20*(60+40)+10*(90+110)+10*(160+140) = 7000 meters

Total cost = cost per meter of load moved * Cumulative load distance = 0.5*7000 = $ 3,500

122. B. 2

There are two possible layouts, X and Y can switch places.

Layout 1

I	II	III
X	Z	Y

Layout 2

I	II	III
Y	Z	X