Question

Write a balanced net ionic equation to show why the solubility of Zn(CN)2(s) increases in the presence of a strong acid and calculate the equilibrium constant for the reaction of this sparingly soluble salt with acid.Write a balanced net ionic equation to show why the solubility of Zn(CN)2(s) increases in the presence of a strong acid and cWrite a balanced net ionic equation to show why the solubility of Ca(OH)2(s) increases in the presence of a strong acid and c

I really need help with both because I am on my last attempt and cannot seem to understand exactly how to solve for K. Thank you for your help! I will be sure to rate your answer if it is correct.

Write a balanced net ionic equation to show why the solubility of Zn(CN)2(s) increases in the presence of a strong acid and calculate the equilibrium constant for the reaction of this sparingly soluble salt with acid. Use the pl-down boxes to pecify states such as (ag) or(o)
Write a balanced net ionic equation to show why the solubility of Ca(OH)2(s) increases in the presence of a strong acid and calculate the equilibrium constant for the reaction of this sparingly soluble salt with acid. Use the pull-down boxes to specify states such as (aq) or (s)
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Answer #1

Q1. The balanced net ionic equation is :

Zn(CN)2 (s) + 2 H3O+ (aq) \rightarrow Zn2+ (aq) + 2 HCN (aq) + 2 H2O (l)

K = 8.0 x 1016

Q2. The balanced net ionic equation is :

Ca(OH)2 (s) + 2 H3O+ (aq) \rightarrow Ca2+ (aq) + 2 H2O (l)

K = 7.9 x 1022

Explanation

Q1. K = (Ksp Zn(CN)2) / (Kw)2

K = (8.0 x 10-12) / (1.0 x 10-14)2

K = (8.0 x 10-12) / (1.0 x 10-28)

K = 8.0 x 1016

Q2. K = (Ksp Ca(OH)2) / (Kw)2

K = (7.9 x 10-6) / (1.0 x 10-14)2

K = (7.9 x 10-6) / (1.0 x 10-28)

K = 7.9 x 1022

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