Question

A five-sided closed field traverse has the following distances in meters: AB = 51.766;
BC = 26.947; CD = 37.070; DE = 35.292; EA = 19.192. The adjusted angles are as
follows: A = 101°03′19″; B = 101°41′49″; C = 102°22′03″; D = 115°57′20″; E =
118°55′29″. The bearing of AB is N 73°00′00″ E. BC is in the S.E. quadrant.The
coordinates of the five(5) corners of the traverse have been computed to be as follows:
Corner "A" X Coordinate 1000.000 Y Coordinate 1000.000
Corner "B" X Coordinate 1050.019 Y Coordinate 1013.314
Corner "C" X Coordinate 1062.085 Y Coordinate 989.218
Corner "D" X Coordinate 1033.262 Y Coordinate 965.900
Corner "E" X Coordinate 1001.292 Y Coordinate 980.852
The area of the traverse using the coordinate method is 1,857 Square meters.
If you used the area computation method we used in class and on the homeworks, the
computed number using coordinate method for area computation for corner "C"
is_______?

Answer 1

0 totWI codno33y Com Cotn Comer compulefed Numke otc tot 3 31 9$9、218

2. ,"Cormple