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If two loads are applied to a beam as shown in the a The weight If the weight of the beam is random, the of the beam itself c
0 1
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Answer #1

a) The random variable representing the bending moment is

r14 0

The expected value is

E (M) 98E(W) + 5E (X1) + 10E (X2) E (M) 98 × 1.5 + 5 × 4 + 10 × 8 E (M) = 247

The variance of the moment is

Var (M) = 982Var (W) + 52Var (X) + 10-Var (X2) Var (M) = 982 × 0.254 52 × 12 + 102 × 0.52 Var(M) 56.125

b) We have MN(247,56.125) . The probability,

M47,5 M-247 300-247 MN(247,56.125) V56.125 V56.125 P (M < 300)- P (Z < 7.0745316) P (M , 300) Φ (7.0745316)

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