Question
how to get cross sectional area
EXAMPLE on tho CANTILEYER METHOD Or LATEIRAL LOADS on FRAMES oblewnry (approximately) fbe reachorus at Ho base of tte Shouw h
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GIVEN STRUCTURE & DATA 8 kips 12 ft 10 kips 16 ft 20 ft 25 ft 15 ft Ratio of areas of columns 10 10 CALCULATIONS LOCATION OFAXIAL FORCES TOP STOREY 8 kips 20 15 25 P21 P22 P23 P24 A1 A2 28.53 25 A4 P22 8.53 P21 28.53 0.3 P21 P23 6.47 P21 28.53 0.23P23 X 25 0 Solving, we get 0.62 kips 0.19 kips 0.14 kips -0.68 kips (tension) (tension) (compression) (compression) P21 P22 P10 20 P11 x60 P12 x40 P13 x 25- 0 Solving, we get P21 P22 P23 P24 3.09 kips 0.93 kips -0.71 kips 3.40 kips (tension) (tensionFORCES IN FRAME MEMBERS 6.18 6.046 8.293 12.226 6.18 14.339 6.18 6.046 8.293 24.7 2636.548 24.074 08 6.1 18.52 14,339 33.815

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