The half-life of 27Mg is 9.50 min.
(a) Initially there were 4.10 × 101227Mg
nuclei present. How many 27Mg nuclei are left 25.5 min
later? Please give your answer to 2 significant figures.
b) Calculate the 27Mg activities (in Ci) at t = 0 and t = 25.5 min.
t= 0 __Ci
t= 25 __ Ci
In order to calculate the number of nuclei present ,the information about the half decay is needed.The half life of this decay follows the first order kinetics. So,Here, N(f ) is the number of nuclei remaining after 25.5 min and N(o) is the number of nuclei at the initial ( t= 0 min)
The half-life of 27Mg is 9.50 min. (a) Initially there were 4.10 × 101227Mg nuclei present. How ...
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