Question

7. The energy levels of the hydrogen atom in the absence of external magnetic field are given by 13.6eV Consider a hydrogen a
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Answer #1

a) energy in 1st state

= -13.6 / 1^2 * 1.6*10^-19 = 2.176*10^-18 J

E = hf

f = E/h = 6.626*10^-34 / (2.176*10^-18)

       = 3*10^-16 Hz

b) if the frequency id doubled

it will move to higher state

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