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4. Consider the Bode Plots for G(s) (a) In a frequency region where the Bode phase curve is decreasing, which direction is th

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Answer #1

(a) Since phase or angle curve is decreasing, therefore, the nyquist curve must be moving in the clock-wise direction.

(b) This problem is very simple ==>

Polar coordinates of the points in the nyquist or plot = (\left | G(j\omega ) \right |, \phi (\omega ))

Therefore, corresponding complex value = \left | G(j\omega ) \right |e^{j\phi (\omega )} = \left | G(j\omega ) \right |cos{(\phi (\omega ))} + j*\left | G(j\omega ) \right |sin{(\phi (\omega ))} ==> ANSWER

(c) Since, one encirclement = 360 degrees

Therefore, 3 encirclements = 960 degrees ==> ANSWER

(d) No, it is because we don't know the frequency values corresponding to points in the nyquist plot.

For any detailed help, please write in the comments.

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