1. Give the detailed arrow-pushing mechanism for the free radical polymerization of methyl methac...
in LINE ANGLE format please Polymersti 2. Write the reaction mechanism (showing arrows) of the synthesis of polystyrene. 4pts • Include and show arrows in 2 initiation steps with benzoyl peroxide forming the phenyl radical. (this is shown in Figure 9 of the lab- just add all arrows) A propagation step of the styrene (the monomer) and phenyl radical. A second propagation step showing polymer growth by reacting styrene and the radical product of first propagation step. A termination step...
reaction mech: initiation , propagation, and termination of the synthesis of polystyrene Polymersti 2. Write the reaction mechanism (showing arrows) of the synthesis of polystyrene. 4pts • Include and show arrows in 2 initiation steps with benzoyl peroxide forming the phenyl radical. (this is shown in Figure 9 of the lab- just add all arrows) A propagation step of the styrene (the monomer) and phenyl radical. A second propagation step showing polymer growth by reacting styrene and the radical product...
The mechanism for number 2 please Polymers11 2. Write the reaction mechanism (showing arrows) of the synthesis of polystyrene. 4pts Include and show arrows in 2 initiation steps with benzoyl peroxide forming the phenyl radical. (this is shown in Figure 9 of the lab- just add all arrows) • A propagation step of the styrene (the monomer) and phenyl radical. • A second propagation step showing polymer growth by reacting styrene and the radical product of first propagation step. A...
From problem 9.10 in the book. An initial experiment at an eyeglass manufacturer has produced poly(methyl methacrylate), whose monomer is (used in eyeglasses and hard contact lenses) with a number average molecular weight of 143,000, by carrying out the reaction at 65 °C for 45 minutes. Since the product design group has determined that a molecular weight of 100,000 is satisfactory, how fast can you speed up the production process and still achieve the desired MW? The activation energies for...
pleas help 5,6,7,8,9,10 III IV 5. The product of free-radical halogenation reactions is an alkyl halide. The major amount of this halide forms during the second step of propagation. However, you should be aware that one possible termination step also forms alkyl halides. Why does the majority of the alkyl halide product come from the propagation step and not the termination step? A. At any given time during the reaction, the concentration of both the alkyl radical and the halide...