uppose a particle of ionizing radiation deposits 1.00 MeV in the gas of a Geiger tube, all of which goes to creating ion pairs. Each ion pair requires 30.0 eV of energy.
(a)
The applied voltage sweeps the ions out of the gas in 1.70 µs. What is the current (in A)?
__________A
(b)
This current is smaller than the actual, since the applied voltage in the Geiger tube accelerates the separated ions, which then create other ion pairs in subsequent collisions. What is the current (in A) if this last effect multiplies the number of ion pairs by 960?
___________A
Uppose a particle of ionizing radiation deposits 1.00 MeV in the gas of a Geiger tube, all of whi...
Ionizing radiation enters a Geiger tube with 1.45 MeV of energy. As the radiation passes through the tube, all of this energy goes into creating ion pairs and each ion pair requires 30 eV of energy. (a) If an applied voltage sweeps these ions out of the gas in 1.30 µs, determine the current (in A). (b) Since the applied voltage in the Geiger tube accelerates these separated ions, creating other ion pairs in subsequent collisions, the actual current is...
Question 10 20 pts Suppose a particle of ionizing radiation deposits 0.86 MeV in the gas of a Geiger tube, all of which goes to creating ion pairs. Each ion pair requires 29.8 eV of energy. The applied voltage sweeps the ions out of the gas in 0.7 us. What is the current in nA?
An energy of 26.0 eV is required to ionize a molecule of the gas inside a Geiger tube, thereby porducing an ion pair. Suppose a particle of ionizing radiation deposits 0.420 MeV of energy in this Geiger tube. What maximum number of ion pairs can it create? I got 16153.83 pairs and for some reason this is only partially correct. Any help is appreciated!!