expected frequency table:
Ei=row total*column total/grand total | Population 1 | Population 2 | Population 3 | Population 4 | Total |
Row 1 | 33.376 | 64.318 | 90.045 | 95.260 | 283 |
Row 2 | 32.314 | 62.273 | 87.182 | 92.231 | 274 |
Row 3 | 30.310 | 58.409 | 81.773 | 86.509 | 257 |
total | 96 | 185 | 259 | 274 | 814 |
c)critical value of X2 =14.449
the rejection region is on the right of the critical value of X2
the non rejection region is on the left of the critical value of X2
value of the test statistic X2 =24.254
reject HO
2 The rejection region is of the critical value of x on the right on the left n region is of the ...
Chapter 11, Section 11.3, Problem 021 Consider the following contingency table that is based on a sample survey. Column 1 Column 2 Column 3 Row 1 133 83 84 Row 2 90 52 | 91 | Row 3 1367996 a. Write the null and alternative hypotheses for a test of independence for this table. Ho: Rows and columns are H: Row and columns are b. Calculate the expected frequencies for all cells assuming that the null hypothesis is true. b....
Identify the null and alternative hypothesis and find the critical t-value(s), t0, and the rejection region(s) for a t-test to test the claim that μ1 ≠ μ2. Assume that the variance is equal between the populations and use α = 0.10. Assume n1 = 50 and n2 = 45. H0: Ha: T0 = Rejection Region =
Question: GRAPH the rejection region, p-value and critical value. (Create the normal distribution curve) Explain why we failed to reject the null hypothesis, the significance of this ALL OF THE DATA IS ALREADY PROVIDED including the critical value, test statistics etc. YOU Don't need to solve anything just GRAPH THE REJECTION REGION, p-value, critical value. etc and explain why we failed to reject the null as provided below. DATA: According to data, 72.4% of the population in Kahului, Maui drive...
Find the critical value(s) and rejection region(s) for a lon-tailed chi-square test with a sample size ne 12 and level of significance 0.05. Click the icon to view the Chi-Square Distribution Table Find the critical value(s). (Round to three decimal places as needed. Use a comma to separate answers as needed.) Find the rejection region(s). Choose the correct answer below. Ов, OA ර ර ව ර ර ව OD Oc Hide Stop sharing ick to select your answer(s). Il auto.proctoru.com...
please help Find the critical value and rejection region for the type of chi are test with sample size n and level of significance a. Two-tailed test n 12, a- 0.05 x2L = 4.575-X2R = 1 9.675; x2 < 4.575, x2 > 19.6 OX2L=3.816.x2R= 21.920-X2< 3.81 6.x2-1.920 。X2L = 2.603, X2R = 26.757: Χ2 < 2.6c x2 > 26.757 X2L = 3.053, X2R = 24.725; X2 ,053-X2 > 24.725 .5 QUESTION 22 Find the rejection region for the specified hypothesis...
Bus 15. If the value of the test statistic is in the rejection region when a = .05, then A)p <.05 B) the decision is to reject the null hypothesis C) the absolute value of the test statistic is larger than the absolute critical value D) All of the above Bis in corree
Find the critical value(s) and rejection region(s) for the type of z-test with level of significance a. Include a graph with your answer. Two-tailed test, α = 0.04 The critical value(s) is/are z Round to two decimal places as needed. Use a comma to separate answers as needed.) Select the correct choice below and, if necessary, fill in the answer box to complete your choice. Round to two decimal places as needed.) A. The rejection regions are z< and z>...
(b) Use technology to find the critical value(s) and identify the rejection region(s). (c) Find the standardized test statistic, t. (d) Decide whether to reject or fail to reject the null hypothesis. (e) Interpret the decision in the context of the original claim. 7.3.23-T Question Help Test a claim that the mean amount of carbon monoxide in the air in U.S. cities is less than 2.33 parts per million. It was found that the mean amount of cartxon monoxide in...
15) Find the critical value that defines the rejection region for the following hypothesis test: Is the average life expectancy of Americans more than 78.8 years? To test this claim, a sample of 400 Americans are studied, with an average lifespan of 79.4 years and a standard deviation of 3.9 years. Use a significance level of 0.05. A) 1.649 B) 1.645 C) 3.08 D) -1.649 E) None of the Above 16) A large software company gives job applicants a test...
15) Find the critical value that defines the rejection region for the following hypothesis test: Is the average life expectancy of Americans more than 78.8 years? To test this claim, a sample of 400 Americans are studied, with an average lifespan of 79.4 years and a standard deviation of 3.9 years. Use a significance level of 0.05. A) 1.649 B) 1.645 C) 3.08 D) -1.649 E) None of the Above 16) A large software company gives job applicants a test...