For the reaction I2(g) + Cl2(g)2ICl(g) ΔG° = -30.4 kJ and ΔS° = 11.4 J/K at 317 K and 1 atm. The maximum amount of work that could be done by this reaction when 2.17 moles of I2(g) react at standard conditions at this temperature is kJ.
maximum work done = -dG
for 1 mole I2 : dG= -30.4 Kj
for 2.17 mole I2: dG= 2.17 x -30.4 KJ= -65.968 KJ
Hence maximum work done= -dG = 65.968 KJ
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Thank you!
For the reaction I2(g) + Cl2(g)2ICl(g) ΔG° = -30.4 kJ and ΔS° = 11.4 J/K at 317 K and 1 atm. The ...
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