Note 1: all calculation is for Temperature = 33oC
We have
molar mass of Borax = 381.37g mol-1
moles of Borax = mass of Borax taken / molar mass of Borax
= 18.41g / 381.37g mol-1
= 0.04827 moles
molarity of Borax solution = moles of Borax/ Volume of solution in L
volume of Borax solution = 70ml/1000ml L-1
= 0.04827 moles / 0.070L
= 0.689M
Now, Ksp = [Na+]2 [B4O5(OH)42-]
= 4x3
[B4O5(OH)42-] = x = 0.689M
[Na+] =2x
so, Ksp = 4 * [ 0.689 ]3 = 1.3083
ln Ksp = ln [1.3083] = 0.2688
Note 2: moles of HCl = volume of HCl used in titration * molarity of HCl
Similer calculation can be done for the other temperature also.
hope this helps!
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