Problem #4 (20 points): A squa of 0.1 g per centimeter of length and is pivoted about side ab on ...
The rectangular loop of wire shown in the figure (Figure 1) has a mass of 0.17 g per centimeter of length and is pivoted about side ab on a frictionless axis. The current in the wire is 8.3 A in the direction shown. Part A Find the magnitude of the magnetic field parallel to the y-axis that will cause the loop to swing up until its plane makes an angle of 30.0° with the yz-plane. Part B Find the direction of the magnetic field...
Problem 27.69 3 of 15 The rectangular loop of wire shown in the figure (Figure 1) has a mass of 0.11 g per centimeter of length and is pivoted about side ab on a frictionless axis. The current in the wire is 8.1 A in the direction shown Part A Find the magnitude of the magnetic field parallel to the y-axis that will cause the loop to swing up until its plane makes an angle of 30.0° with the yz-plane...
A rectangular loop has dimensions 0.505 m by 0.260 m. The loop is hinged along the x-axis and lies in the xy-plane (see the figure below). A uniform magnetic field of 1.45 T is directed at an angle of 40.0° with respect to the positive y-axis and lies parallel everywhere to the yz-plane. The loop carries a current of 0.855 A in the direction shown. (Ignore gravitation.) (a) In what direction is magnetic force exerted on wire segment ab? direction...
4. [-12 Points] DETAILS SERPSET9 30.P.007. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A conductor consists of a circular loop of radius R = 23.0 cm and two long, straight sections as shown in the figure below. The wire lies in the plane of the screen and carries a current I = 3.80 A. Find the magnetic field at the center of the loop. magnitude NT direction -Select- V R Additional Materials eBook
Write neat please. Show step by step please. Read instructions carefully. Box in answer please. Thank you Chapter 28 for you. torrono FB = q vxB FB = q vB sin o r =mv qB VB Rm K=mv2 = open 1_2 21 21 vwqB EF =qE + qvxB VE m_rB, B k 1 mv2_qBR qE FB = |LXB Tmax = 1 AB Tmax = 1 A x B = uxB = IA U=-.B EH = V.B AV - Ed =...