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Problem #4 (20 points): A squa of 0.1 g per centimeter of length and is pivoted about side ab on ...
The rectangular loop of wire shown in the figure (Figure 1) has a mass of 0.17 g per centimeter of length
The rectangular loop of wire shown in the figure (Figure 1) has a mass of 0.17 g per centimeter of length and is pivoted about side ab on a frictionless axis. The current in the wire is 8.3 A in the direction shown. Part A Find the magnitude of the magnetic field parallel to the y-axis that will cause the loop to swing up until its plane makes an angle of 30.0° with the yz-plane. Part B Find the direction of the magnetic field...
Problem 27.69 3 of 15 The rectangular loop of wire shown in the figure (Figure 1)...
Problem 27.69 3 of 15 The rectangular loop of wire shown in the figure (Figure 1) has a mass of 0.11 g per centimeter of length and is pivoted about side ab on a frictionless axis. The current in the wire is 8.1 A in the direction shown Part A Find the magnitude of the magnetic field parallel to the y-axis that will cause the loop to swing up until its plane makes an angle of 30.0° with the yz-plane...
A rectangular loop has dimensions 0.505 m by 0.260 m. The loop is hinged along the...
A rectangular loop has dimensions 0.505 m by 0.260 m. The loop
is hinged along the x-axis and lies in the xy-plane (see the figure
below). A uniform magnetic field of 1.45 T is directed at an angle
of 40.0° with respect to the positive y-axis and lies parallel
everywhere to the yz-plane. The loop carries a current of 0.855 A
in the direction shown. (Ignore gravitation.)
(a) In what direction is magnetic force exerted on wire segment
ab?
direction...
4. [-12 Points] DETAILS SERPSET9 30.P.007. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A conductor consists...
4. [-12 Points] DETAILS SERPSET9 30.P.007. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A conductor consists of a circular loop of radius R = 23.0 cm and two long, straight sections as shown in the figure below. The wire lies in the plane of the screen and carries a current I = 3.80 A. Find the magnetic field at the center of the loop. magnitude NT direction -Select- V R Additional Materials eBook
Write neat please. Show step by step please. Read instructions carefully. Box in answer please. Thank...
Write neat please. Show step by step please. Read instructions
carefully. Box in answer please. Thank you
Chapter 28 for you. torrono FB = q vxB FB = q vB sin o r =mv qB VB Rm K=mv2 = open 1_2 21 21 vwqB EF =qE + qvxB VE m_rB, B k 1 mv2_qBR qE FB = |LXB Tmax = 1 AB Tmax = 1 A x B = uxB = IA U=-.B EH = V.B AV - Ed =...
Problem 27.69 3 of 15 The rectangular loop of wire shown in the figure (Figure 1) has a mass of 0.11 g per centimeter of length and is pivoted about side ab on a frictionless axis. The current in the wire is 8.1 A in the direction shown Part A Find the magnitude of the magnetic field parallel to the y-axis that will cause the loop to swing up until its plane makes an angle of 30.0° with the yz-plane...
A rectangular loop has dimensions 0.505 m by 0.260 m. The loop
is hinged along the x-axis and lies in the xy-plane (see the figure
below). A uniform magnetic field of 1.45 T is directed at an angle
of 40.0° with respect to the positive y-axis and lies parallel
everywhere to the yz-plane. The loop carries a current of 0.855 A
in the direction shown. (Ignore gravitation.)
(a) In what direction is magnetic force exerted on wire segment
ab?
direction...
4. [-12 Points] DETAILS SERPSET9 30.P.007. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A conductor consists of a circular loop of radius R = 23.0 cm and two long, straight sections as shown in the figure below. The wire lies in the plane of the screen and carries a current I = 3.80 A. Find the magnetic field at the center of the loop. magnitude NT direction -Select- V R Additional Materials eBook
Write neat please. Show step by step please. Read instructions
carefully. Box in answer please. Thank you
Chapter 28 for you. torrono FB = q vxB FB = q vB sin o r =mv qB VB Rm K=mv2 = open 1_2 21 21 vwqB EF =qE + qvxB VE m_rB, B k 1 mv2_qBR qE FB = |LXB Tmax = 1 AB Tmax = 1 A x B = uxB = IA U=-.B EH = V.B AV - Ed =...
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