Question

A machine part is vibrating along the x-axis in simple harmonic motion with a period of 0,29 s an...

A machine part is vibrating along the x-axis in simple harmonic motion with a period of 0,29 s and a range (from the maximum in one direction to the maximum in the other) of 4,8 cm. At time t = 0 it is at its central position and moving in the +x direction. What is its position (cm) when t = 49 s? Answer in two decimal places.

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Answer #1

Solution)

We know,

x = A sin(ωt)

Hete, amplitude,

A = (4.8 cm) / 2

A = 2.4 cm

Angular velocity,

ω = 2π / T

ω = 2π / (0.29 s)

Also, at time t = 49 s,

x = (2.4 cm) sin( [2π / (0.29 s)] × (49 s) )

x = -0.775 cm

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