You have four solutions below. a) pure water b) 0.400M solution of C5H5N and 0.250 M C5H5NHBr c) 0.500M solution of C5H5NHBr d) 0.500M solution of pyridine, C5H5N. (Kb=1.7 x 10-9) Find the pH of a, b, and d. Show all work with steps.
You have four solutions below. a) pure water b) 0.400M solution of C5H5N and 0.250 M C5H5NHBr c) ...
Find the [OH−] of a 0.40 M pyridine (C5H5N) solution. (The value of Kb for pyridine (C5H5N) is 1.7×10−9.) Find the pH of a 0.40 M pyridine (C5H5N) solution.
Calculate the pH of a 0.20 M solution of the weak base pyridine. (C5H5N; Kb = 1.7 x 10-9). What is the pH of a 0.20 M solution of NH4Cl? [Kb(NH3) = 1.8 ´ 10–5]
16 What is the pH of a 1.63 M solution of pyridine (C5H5N; Kb = 1.7 x 10-9)? [ (4 Puan) 9.72 10.07 9.07 5.23 8.77
Part 1 (a) Calculate the pH at 25°C of a 0.10 M solution of a weak base with a Kb of 2.6 ×10−11 Part 2 (a) Calculate the pH for each of the following solutions at 25°C. (b) 0.12 M NH3 (Kb for NH3 = 1.8 ×10−5) (c) 0.050 M C5H5N (pyridine). (Kb for pyridine = 1.7 × 10−9)
1))))Weak Base Titration: At the Equivalence Point a))A 11.30 mL solution of 2.47 M pyridine (C5H5N, a weak base) is titrated to the equivalence point with 22.4 mL of HNO3. What is the pH at the equivalence point? Kb for pyridine is 1.7 X 10-9. b))))Click on all of the dominant species that you would expect to find in solution at the equivalence point. Do not include H3O+ and OH-ions unless they are coming from another source other than the...
What is the pH of a .62 M [C5H5NH]NO3 solution? Kb(C5H5N) = 1.7 x 10-9 Kb(NH3) = 1.8 x 10-5
Determine the pOH of a 0.098 M C5H5N solution at 25°C. The Kb of C5H5N is 1.7 × 10-8. A. A) 4.59 B. B) 9.41 C. C) 3.71 D. D) 4.39 E. E) 4.67 F. F) 1.34 G. G) none of these
You have 15.00 mL of a 0.100 M aqueous solution of the weak base C5H5N (Kb = 1.50 x 10-9). This solution will be titrated with 0.100 M HCl. (a) How many mL of acid must be added to reach the equivalence point? (b) What is the pH of the solution before any acid is added? (c) What is the pH of the solution after 10.00 mL of acid has been added? (d) What is the pH of the solution...
Consider a 1.0-L solution that is 0.480 M C5H5N and 0.17 M C5H5NHCl at 25 °C. What is the pH of this solution before and after 0.012 moles of HI have been added? Kb of C5H5N is 1.7E-9 a-initial pH: 4.78, final pH: 5.72 .b- initial pH: 5.68, final pH: 5.64 .c- initial pH: 5.68, final pH: 5.74. d-initial pH: 5.23, final pH: 4.82. e-initial pH: 5.68, final pH: 4.82
You have a 0.776 M solution of the base pyridine. Kb = 1.7 x 10" Find the pH of the pyridine solution. Round your answer to two places past the decimal. Type your answer...