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f the solubility product 1. How many grams of Ag CrO4 will dissolve in pure water i constant for silver chromate is 1.1 x 101

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Answer #1

1.sol:

Ag2CrO4 = 2Ag+ + CrO42-

s 2s s

Ksp = [2s]2[s] = 4s3 , Ksp= 1.1 x 10-12 (given)

s3 = Ksp/4 = 1.1 x 10-12 / 4 = 0.275 x 10-2

s3= 0.275 x 10-2  

3logs = log(0.275 x 10-2) ; log s = -0.8536 ; s = antilog(-0.8536) = 14.01 x 10-2 mol/L

hence , s = 14.01 x 10-2 mol/L

S = 14.01 x 10-2 x 331.74g/L = 46.48g/L , (Ag2CrO4 mol.wt. = 331.74 g/mol)

hence, 46.48g Ag2CrO4 will dissolve in 1L water.

2.ans Data value for H , S ,G calculation not given.

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