Question

hole-body scan? the same total amount of energy to the body of 75 kg person as one w (Number of chest x rays - 600) Q10:(+)) А 67 kg person accidently ingests 0.35 Ci of tritum (t1/2 3.88 x 10%). Assume that the tritium spreads uniformly throughout the body and that each decay leads on the average to the absorption of 5.0 keV of energy from the electrons (RBE-1) emitted in the decay. Calculate A. the initial number of tritium nuclei in the ingested sample B. the number of undecayed nuclei one week after ingestion C. the number of decayed nuclei one week after ingestion D. the absorbed dose (in rad) during one week E. the equivalent dose (in mSv) during one week (7.25050 x 1018 nucle) (7.24267 x 1018 nuclei) (7.82454 x 1015 nuclei) (9.34 rad) (93.4 mSv) Dr. Abdallah Ahmad Almahasneh Associate Professor of Physics

Ph

Answer 1

muclii tm IVOカ N, dT 〉, decay - 0. 693 CIT eslien d て

clu one Weel ST we aleulst. utry ev Et S-000 x 116乂10

wiem m67 6.a59) ·0934 J ワ Week