Solution :-
1.
Here
One will use two way ANOVA with interactions to check effect of
temperature and copper content on the response variable. Df Sum Sq
Mean Sq F value Pr(>F)
x1 3 533.6 177.86 22.858 5e-06
x2 3 156.1 52.03 6.687 0.0039
x1*x2 9 262.5 . 29.17 3.749 0.0104
Residuals 16 124.5 7.78
P-value for interaction between temperature and copper content = 0.0104 > 0.01,
so at 1% level of significance, we fail to reject H0 and we can conlcude that there is no significant effect of interaction between temperature and copper content in the response variable.
P-value for temperature = 0.0039 < 0.01
and P-value for copper content = 0.000005 < 0.01
so at 1% level of significance we can conclude that there is significant effect of temperature and copper content in response variable.
Provide R code solution. Explanation and details. 4. Question 5.7. Johnson and Leone (Statistics and Experimental Design in Engineering and the Physical Sciences, Wiley, 1977) describe an experim...
Johnson and Leone describe an experiment to investigate warping of copper plates. The two factors studied were the temperature and the copper content of the plates. The response variable was a measure of the amount of warping. The data are as follows: Copper Content(%) Temperature 406080 100 50 75 100 125 17, 20 16,21 24,22 28, 27 12,9 18, 13 17, 12 27, 31 16, 12 18,2 25,2330, 23 21,17 23, 21 23, 22 29, 31 We were unable to...