Stack with the activation record instances :
3. Show the stack with all activation record instances, including static and dynamic chains, when execution reaches position 1 in the following skeletal program. Assume Bigsub is at level 1 procedure...
Show the stack with all activation record instances, including static and dynamic chains, when execution reaches position 1 in the following ske- letal program. Assume Bigsub is at level 1. procedure Bigsub is MySum : Float; procedure A is X : Integer; procedure B(Sum : Float) is Y, Z : Float begin -of B C(Z) end; -- of B begin -of A B (X)i end -- of A procedure C (Plums Float) is begin - of c end; -- of...
.Show the stack with all activation record instances, including static and /dynamic chains, when execution reaches position 1 in the following skel- etal program. Assume bigsub is at level i. function bigsub () function a { function b( { { end of b function c) b) end of c c) // end of a a) )7/ end of bigsub .Show the stack with all activation record instances, including static and /dynamic chains, when execution reaches position 1 in the following...
Show the stack with all activation record instances, including the dynamic chain, when execution reaches position 1 in the following skeletal program. This programuses the deep-access method to implement dynamic scoping.void fun1(){float a;}void fun2(){int b, c;}void fun3(){float d;<--------1}void main(){char e, f, g;}The calling sequence for this program for execution to reach fun3 ismain calls fun2fun2 calls fun1fun1 calls fun1fun1 calls fun3
(24) (2 marks) Consider the following skeletal program, written in a lan- guage with static scope. procedure Main; procedure A procedure B: procedure C begin C end C begin B end B procedure D procedure E begin E end E begin D end D begin A end A begin ain end Nain Imagine that the following procedure calls have taken place: Main calls A A calls D D calls E E calls B B calls C i. Drawthe run time...
Given the following Ada program: procedure Main is X, Y: Integer; procedure Sub1 is Y, Z: Integer; begin -- of Sub1 point 1 Sub2; end; -- of Sub1 procedure Sub2 is X: Integer; procedure sub3 (B: Integer) is W: Integer; begin -- of Sub3 point 2 end; -- of Sub3 begin -- of Sub2 point 3 Sub3 (X); end; -- of Sub2 begin -- of Main point 4 Sub1; end; -- of Main For each of the four marked points,...