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5) Given the function fix.y) - x2 and region R bounded by x 0, y x and 2x+y 6 (a) Sketch the region R (label lines, intercepts, axes and shade region) (b) SET UP the integral over this region (c)...
The region R is bounded by the x-axis and y = V16 – x2 a) Sketch...
The region R is bounded by the x-axis and y = V16 – x2 a) Sketch the bounded region R. Label your graph. b) Set up the iterated integral to solve for the area of the bounded region using either the Rx region or Ry region. Do not integrate. Evaluate the integral using polar coordinates for the region R. sec(x2 + y2) tan(x2 + y2) da c) R
2) The region R is bounded by the x-axis and y = V16 - x2 a)...
2) The region R is bounded by the x-axis and y = V16 - x2 a) (0.75 point) Sketch the bounded region R. Label your graph. b) (0.75 point) Set up the iterated integral to solve for the area of the bounded region using either the Ry region or Ry region. Do not integrate. c) (1.25 point) Evaluate the integral using polar coordinates for the region R. sec(x2 + y2) tan(x2 + y2) dA R
2) The region R is bounded by the x-axis and y = V16 - x2 a)...
2) The region R is bounded by the x-axis and y = V16 - x2 a) (0.75 point) Sketch the bounded region R. Label your graph. b) (0.75 point) Set up the iterated integral to solve for the area of the bounded region using either the Rx region or Ry region. Do not integrate. c) (1.25 point) Evaluate the integral using polar coordinates for the region R. sec(x2 + y2) tan(x2 + y2) dA R
2) The region R is bounded by the x-axis and y = V16 – x2. a)...
2) The region R is bounded by the x-axis and y = V16 – x2. a) (0.75 point) Sketch the bounded region R. Label your graph. b) (0.75 point) Set up the iterated integral to solve for the area of the bounded region using either the Rx region or Ry region. Do not integrate. c) (1.25 point) Evaluate the integral using polar coordinates for the region R. S sec(x2 + y2) tan(x2 + y2) da R
2) The region R is bounded by the x-axis and y = V16 – x2 a)...
2) The region R is bounded by the x-axis and y = V16 – x2 a) (0.75 point) Sketch the bounded region R. Label your graph. b) (0.75 point) Set up the iterated integral to solve for the area of the bounded region using either the Rx region or Ry region. Do not integrate. c) (1.25 point) Evaluate the integral using polar coordinates for the region R. S sec(x2 + y2) tan(x2 + y2) da R
Problem 5 [10 points] Set up integrals for both orders of integration. Use the more convenient order to evaluate the integral over the plane region R: A R region bounded by y 0, y x, x 4 R 1+x2 a...
Problem 5 [10 points] Set up integrals for both orders of integration. Use the more convenient order to evaluate the integral over the plane region R: A R region bounded by y 0, y x, x 4 R 1+x2 a) [2 points] First order b) [2 points] Second order c) [6 points] Evaluate the integral using the more convenient order
Problem 5 [10 points] Set up integrals for both orders of integration. Use the more convenient order to evaluate the...
4. 5. (a) Sketch the region bounded by y- +2x-4, y-x2+4x-4 clearly indicating vertices on the gra...
4. 5. (a) Sketch the region bounded by y- +2x-4, y-x2+4x-4 clearly indicating vertices on the graph, (b) Draw the area element AA on the graph and find a general expression for A4. (c) Set up a definite integral for A and find the area.
4. 5. (a) Sketch the region bounded by y- +2x-4, y-x2+4x-4 clearly indicating vertices on the graph, (b) Draw the area element AA on the graph and find a general expression for A4. (c) Set...
Let R be the tetrahedron bounded by the planes x = 0, y = 0, :...
Let R be the tetrahedron bounded by the planes x = 0, y = 0, : = 0 and 6x+5y+ 92 = 4. The volume of R is given by Calculate the values of the following: a b= C de fo g A two-dimensional lamina occupies the triangle bounded by the lines r = 0, y = 4 1 and 3 3+ 4y = 6. The lamina has density function of p=9x² +5. The mass of the plate is given...
sketch please! 1. Sketch and set up the integral of the region bounded by x =...
sketch please!
1. Sketch and set up the integral of the region bounded by x = 8+2y- y2 and x+y=-2. (15 pts) a) Rotate about the line x=-7. b) Rotate about the line y = 5.
40 1. 16 pts) Evaluate the integral( quadrant enclosed by the cirle x + y2-9 and the lines y - 0 ...
Please do #2
40 1. 16 pts) Evaluate the integral( quadrant enclosed by the cirle x + y2-9 and the lines y - 0 and y (3x-)dA by changing to polar coordinates, where R is the region in the first 3x. Sketch the region. 2. [6 pts) Find the volume below the cone z = 3、x2 + y2 and above the disk r-3 cos θ. your first attempt you might get zero. Think about why and then tweak your integral....
The region R is bounded by the x-axis and y = V16 – x2 a) Sketch the bounded region R. Label your graph. b) Set up the iterated integral to solve for the area of the bounded region using either the Rx region or Ry region. Do not integrate. Evaluate the integral using polar coordinates for the region R. sec(x2 + y2) tan(x2 + y2) da c) R
2) The region R is bounded by the x-axis and y = V16 - x2 a) (0.75 point) Sketch the bounded region R. Label your graph. b) (0.75 point) Set up the iterated integral to solve for the area of the bounded region using either the Ry region or Ry region. Do not integrate. c) (1.25 point) Evaluate the integral using polar coordinates for the region R. sec(x2 + y2) tan(x2 + y2) dA R
2) The region R is bounded by the x-axis and y = V16 - x2 a) (0.75 point) Sketch the bounded region R. Label your graph. b) (0.75 point) Set up the iterated integral to solve for the area of the bounded region using either the Rx region or Ry region. Do not integrate. c) (1.25 point) Evaluate the integral using polar coordinates for the region R. sec(x2 + y2) tan(x2 + y2) dA R
2) The region R is bounded by the x-axis and y = V16 – x2. a) (0.75 point) Sketch the bounded region R. Label your graph. b) (0.75 point) Set up the iterated integral to solve for the area of the bounded region using either the Rx region or Ry region. Do not integrate. c) (1.25 point) Evaluate the integral using polar coordinates for the region R. S sec(x2 + y2) tan(x2 + y2) da R
2) The region R is bounded by the x-axis and y = V16 – x2 a) (0.75 point) Sketch the bounded region R. Label your graph. b) (0.75 point) Set up the iterated integral to solve for the area of the bounded region using either the Rx region or Ry region. Do not integrate. c) (1.25 point) Evaluate the integral using polar coordinates for the region R. S sec(x2 + y2) tan(x2 + y2) da R
Problem 5 [10 points] Set up integrals for both orders of integration. Use the more convenient order to evaluate the integral over the plane region R: A R region bounded by y 0, y x, x 4 R 1+x2 a) [2 points] First order b) [2 points] Second order c) [6 points] Evaluate the integral using the more convenient order
Problem 5 [10 points] Set up integrals for both orders of integration. Use the more convenient order to evaluate the...
4. 5. (a) Sketch the region bounded by y- +2x-4, y-x2+4x-4 clearly indicating vertices on the graph, (b) Draw the area element AA on the graph and find a general expression for A4. (c) Set up a definite integral for A and find the area.
4. 5. (a) Sketch the region bounded by y- +2x-4, y-x2+4x-4 clearly indicating vertices on the graph, (b) Draw the area element AA on the graph and find a general expression for A4. (c) Set...
Let R be the tetrahedron bounded by the planes x = 0, y = 0, : = 0 and 6x+5y+ 92 = 4. The volume of R is given by Calculate the values of the following: a b= C de fo g A two-dimensional lamina occupies the triangle bounded by the lines r = 0, y = 4 1 and 3 3+ 4y = 6. The lamina has density function of p=9x² +5. The mass of the plate is given...
sketch please!
1. Sketch and set up the integral of the region bounded by x = 8+2y- y2 and x+y=-2. (15 pts) a) Rotate about the line x=-7. b) Rotate about the line y = 5.
Please do #2
40 1. 16 pts) Evaluate the integral( quadrant enclosed by the cirle x + y2-9 and the lines y - 0 and y (3x-)dA by changing to polar coordinates, where R is the region in the first 3x. Sketch the region. 2. [6 pts) Find the volume below the cone z = 3、x2 + y2 and above the disk r-3 cos θ. your first attempt you might get zero. Think about why and then tweak your integral....
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