Question

2. Managers of a transit system want to evaluate four types of tires with respect to wear. Three buses are being used for a t

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Answer #1

data

tire 1 tire 2 tire 3 tire 4
9.1 17.1 20.8 11.8
13.4 20.3 28.3 16
15.6 24.6 23.7 16.2

Using Excel

Anova single factor

Anova: Single Factor
SUMMARY
Groups Count Sum Average Variance
tire 1 3 38.1 12.7 10.93
tire 2 3 62 20.66667 14.16333
tire 3 3 72.8 24.26667 14.30333
tire 4 3 44 14.66667 6.173333
ANOVA
Source of Variation SS df MS F P-value F crit
Between Groups 256.6825 3 85.56083 7.510277 0.01031 4.066181
Within Groups 91.14 8 11.3925
Total 347.8225 11

a)

SST = 347.8225

SSM + 256.6825

SSE = 91.14

b)

F = 7.5103

p-value = 0.0103

p-value < alpha(0.05)

hence we reject the null hypothesis

we conclude that there is significant difference of wear between tire types

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2. Managers of a transit system want to evaluate four types of tires with respect to wear. Three buses are being used for a test drive with one tire of each type placed randomly on the four wheels of...
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