Given
n1 = 31
s1 = 45.1
s12 =
2034.01
n2 = 31
s2 = 82.1
s22 =
6740.41
Let α = 0.05 5% level of
significance
Let σ1 , σ2 be the population standard
deviations
Hence null and alternative hypothesis are
Ho : σ12 = σ22
H1 : σ12 ≠
σ22
We find the critical F-value from the F-tables for
α=0.05
α/2 = 0.025 , 1- α/2 = 0.975
and degrees of freedom (n1 -1 = 30) and (n2 - 1 =
30)
Since this is a two way test, we get two F-crit
values
F1 = F.INV(0.025, 30, 30) = 0.482
F2 = F.INV(0.975, 30, 30) =
2.074
Thus we reject Ho if F-calc < 0.482 OR F-calc > 2.074
We now calculate the F-statistic
as
F-calc = 0.3018 (F test
statistic)
0.3018 < 0.482
that is F-calc < F1
Hence, we reject Ho
Formal Statement
There is sufficient statistical evidence at 5% level of
significance that
the there is a difference between the two
variances.
SD 1= 45.1 SD 2 = 82.1 smalle size is 31 A. 5. F test for 2 standard deviations (Covered in Module 4 - Topic 14) Diagram [1] Hypotheses 12] Ho Hi Calculation of test statistic [1] Reject or fail...
solve for the yellow highlighted please 4 26.9 218 41.6 20.9 23.6 8.4 sample mean 2.6 sample standard deviation 13 0.419 Number of yes Sample proportion 1.000 0.290 0.387 0.613 0.484 Hypothetical Values to use Population mean Population standard deviation Population proportion 12 Use this only for testing the standard deviation 0.600 A. 5. F test for 2 standard deviations (Covered in Module 4 - Topic 14) Hypotheses 12 Diagram [1 Ho Hi Calculation of test statistic Reject or fail...
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