Question

this is Matlab. Three images are consecutive and connected. I NEED PROBLEM 2

Chapter 6 Programming in Matlab Week 6 THE ALTERNATING HARMONIC SERIES The alternating harmonic series converges to the natural log of 2 +--...-In(2) = 0.6931471806 -1--+ Because of this, we can use the alternating harmonic series to approximate the In(2). But how far out do you have to take the series to get a good approximation of the final answer? We can use a while loop to solve this problem. 1. State the Problem Use a while loop to calculate the members of the alternating harmonic sequence and the value of the series until it converges to values that vary by less than.001. Compare the result to the natural log of 2. 2. Describe the Input and Output Input The description of the alternating harmonic series The value of the truncated series, once the convergence criterion is met Plot the cumulative sum of the series elements, up to the point where the convergence criterion is met. Output Start Define first two members of the sequence (1) 1 and y(2)-12 Calculate the first two cumulative totals total)-y(1) total(2) - total(1) +(2) Set the starting index number equal to 3 while the absolute value of adjacent cumulative sums is ter than 0.001 continue False Calculate the next member of the sequence y(A) = Calculate the next cumulative sum total(k) totalk-1)+y(k) Increment the counter k k+1 Print the value of the final element in the sequence the cumulative sum the natural log of 2 Plot the results End

Answer 1

`Hey,

Note: Brother in case of any queries, just comment in box I would be very happy to assist all your queries

clc
clear all
y=[1,-1/2];
total=[1,1/2];
k=3;
while(abs(total(k-1)-total(k-2))>0.001)
y(k)=(-1)^(k+1)/k;
total(k)=total(k-1)+y(k);
k=k+1;
  
end
fprintf('Final element is %f\n',y(end));
disp('Approximation sum is');
total(end)
disp('Natural log(2) is')
log(2)
plot(total)

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