Given that y = 1254.6 x + 0.0189
y = mx + c
y = absorbance
c = concentration of solution
Given that absorbance y = 0.03
concentration x = ?
Hence, 0.03 = 1254.6 x + 0.0189
x = 0.0000088 M
= 8.8 x 10-6 M
Therefore,
concentration of phosphate = 8.8 x 10-6 M
To determine the phosphate concentration in a water sample, the following standard curve was produced. If the absorbance of the water sample is 0.030, what is its phosphate concentration? Standard Cu...
Grade: DETERMINATION OF PHOSPHATE IN WATER 1. Option What is the concentration of phosphate in the original lake water sample if the unknown lake water sample in the option had been diluted by taking 25.0 mL of lake water and diluting it to the indicated final volume? 21.comgy 2. Option Water treatment plants must reduce phosphate levels to 3.2 micromoles PO 3-/L before the water is considered drinkable. If water from Lake Pontchartrain is determined to have a phosphate concentration...
Determination of Phosphate in Water Out-of-Class Exercise 4. Use Data Set I t o answer the following questions a) Make a plot of absorbance versus concentration for the data set. Draw the best straight line or smooth curve (whichever is appropriate). Put the absorbance on the yaxis and concentration on the cas. b) Make a plot of % transmittance versus concentration for the data set. Draw the best straight line or smooth curve (whichever is appropriate). Put the transmittance on...
1. Use the following data to construct a calibration curve and determine the concentration of unknown as given. What is the molar absorptivity of the analyte? The compound solutions were measured in a 0.5 cm path length quartz cuvette. solution [X] (M) Absorbance At 254 nm Standard 1 Standard 2 Standard 3 Standard 4 Standard 5 Sample 0.03584 0.05719 0.1289 0.2305 0.3161 ??? 0.097 0.169 0.365 0.682 0.997 0.719
20. Determine the percent transmittance where the sample's concentration is 7.83 x 104 M. The standard concentration is 3.25 x 103 M with an absorbance of 0.602 and pathlength of 2.00 cm. (Show work) 4 pts) 21. The distribution ratio of a sample is 25.5 between water and ethyl acetate. Suppose that 90.0 mL of water is extracted with 55.7 mL of ethyl acetate. What fraction of the sample remains in aqueous phase (phase 1) for the fourth extractions? What...