Question

8.63 Data for a regenerative vapor power cycle using an open and a closed feedwater heater similar in design to that shown in Fig PS.60 are provided in the table below. Steam enters the hubine at 14 MPa, 560 C, state 1, and expands isentropically in three stages to a condenser of80 kPa, state 4. Saturated liquid exiting the condenser at state 5 İs pumped isentropically to state 6 and enters the open feedwater heater. Between the first and second turbine stages, some steam is extracted at heater. The diverted steam leaves the closed feedwater heater as saturated liquid at 1 MPa, state 10. undergoes a throttling process to 0.2 MPa, state 11, and enters the open feedwater heater Steam is also extracted bethween the second and third turbine stages at 0.2 MPa, state 3, and diverted to the open feedwater heater. Saturated liquid at 0.2 MPa exiting the open feedwater heater at state 7 is pumped isentropically to state S and enters the closed feedwater heater. Feedwater exits the closed feedwater heater at 14 MPa. 170°C. state 9, and then enters the steam generator. If the net power developed by the cycle is 300 MW. determine (a) draw a T-s diagram of the Rankine cycle, with all isobars shown. (b) the cycle thermal efficiency. (c) the mass flow rate into the first turbine stage, in kg's. 1 MPa, state 2, and diverted to the closed feedwater (d) the rate of heat transfer from the working fluid as it passes through the condenser, in MW. StatePa) Jkg) JkgK) 1 | 14.000 | 560 | 3486.0 | 6.5941 | - 2781.6 6.5941 2 1.000 2497.0 6.59410.9048 3 200 4 S0 93.5 2357.6 6.5941 0.8645 80 93.5 391.66 1.2329 391.70 12329 504.70 1.5301 504.71 1.5301 6 200 7 200 8 14.000 9 14.000 170 719.21 2.0419 10 1.000 11 200 762.81 2.1387 0 762.81 2.1861 0.1172

Answer 1

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