Question

Consider the topology shown below with following requirements Three subnets A, B, C, should have enough addresses, starting from 192.100.10.0 to support 500 interfaces, 200 interfaces, and 100 interfaces, respectively. Each of subnets, D, E, and F has 32 interfaces. (not required for address assignment.) The IP addresses for three subnets should be assigned continuously, with spacing of power-2, that means, 250 will be rounded to 256, and so on. For each subnet, the assignment should take the form a.b.c.d/x as subnet mask Answer questions (35) (39). Subnet A R1 Subnet F Subnet D R3 R2 Subnet E Subnet C Subnet B Figure 3: Network Topology (35) What is the subnet mask and lowest/highest address for Subnet A? Subnet-A Mask: Subnet-A Range: in to (36) What is the subnet mask and lowest,/highest address for Subnet B? Subnet-B Mask: Subnet-B Range: from to (37) What is the subnet mask and lowest,/highest address for Subnet C? Subnet-C Mask: Subnet-C Range: to (38) Assume that subnet A has one packet from node A1 (left) sent to node C-2 (right) in subnet C. Write down all IP addresses and (valid) MAC addresses that the packet travels through R1 addresses that follow network assignments are acceptable. Destination IP addr./MAC addr 192.100.10.32/50:50:50:50:50:50 Source IP addr./MAC addr. Legs AT-RI (A) 192.100.10.o/40:40:40:40:40:40 RI(A) RI(F) RI(F) R3(F) R3(F)- R3(C) R3(C)-C2 (39) Now assume that subnet will support an actual number of 1,500 interfaces instead of 500. Therefore, Router R1 will need a Network Address Translation table to serve the purpose by using ONE external or WAN-side IP address for 3 LAN-side terminals with addresses 10.0.0.1, 10.0.0.2, and 10.0.0.3. Fill out the following NAT table with one valid IP address in subnet A and Port numbers for each terminal. LAN side WAN side

Answer 1

Consikder the topology shown below with following reqairements e Three subnets A, B. C, shoukd have enough addresses, starting fromm 192.100.10.0 to support 500 interfac, 200 Interfaces, and 100 indesoces, respeetively. Each of ashnets, D, E, and interfoces. (not required Sor sldress sssignment.) has 32 . The IP addrenses for three subaets shoald be assigued continsoualy, with spacing of power-2, that means, 250 will be rouaded to 256, and so on For ench suubact, the assignment should take the form a.b.c.d/x as subact mask. Answer questioas (35) (39). (3t) What is the suhbuet mak d owest/ihest adtrs for SutrtC Mk: 255.255.255.128 Subnet F Subret-C Range: 125 on 192.100.11.0 192.100.11.1 Subnet C Subnet B 192.100.11.126 Figure 3: Network Topology. (35) What is the subnet mask and lowest,/highest address for Subnet A? Subnet-A Mask: 255.255.254.0 Subnet-A Range: 123 192.100.8.0 192.100.8.1 to 192-100.9.254 (36) What is the subnet mask and lowest/highest address for Subnet B? Subnet-B Mask: 255.255.255.0 Subnet-B Range: n 192.100.10.1 192.100.10.0 /24 to 192.100.10.254 Subnetting Successful Major Network: 192.100.8.0/22 Available IP addresses in major network: 1022 Subnet Needed Size Allocated Size Address Mask Dec Mask /23 /24 /25 Assignable Range Broadcast 192.100.9.255 192.100.10.255 192.100.11.127 255.255.254.0 255.255.255.0 255.255.255.128 510 254 126 192.100.8.0 192.100.10.0 192.100.11.0 500 200 100 192.100.8.1-192.100.9.254 192.100.10.1-192.100.10.254 192.100.11.1 192.100.11.126

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