1. Above is the simple crosstab for Beta Blocker use vs. Low HDL. The natural log of the odds ratio [ln(OR)]= 2. Using the table from question 1, the standard error of ln(OR)= 3. Using the answer for...

Question

Question

Beta Dichotomized low HDL blocker level (abnormal) 2 Total use yes 41 30 7 15 34 15 yes no Total 71 49

1. Above is the simple crosstab for Beta Blocker use vs. Low HDL. The natural log of the odds ratio [ln(OR)]=

2. Using the table from question 1, the standard error of ln(OR)=

3. Using the answer for the two previous questions, calculate a 95% CI for OR (Note, you will have to convert your answer from log form before you select an answer).

math Statistics-And-Probability

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Answer 1

Answer #1

Answer:

34/7 (ORR)4.857143 15/15 And In(4.857143) (1.58045) (//..1.1.1) The formula for 95% Cl for OR is n (ORR) 1.96x | 4-+-+-+ Th

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Answer 2

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1. Above is the simple crosstab for Beta Blocker use vs. Low HDL. The natural log of the odds ratio [ln(OR)]= 2. Using the table from question 1, the standard error of ln(OR)= 3. Using the answer for...

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1. Above is the simple crosstab for Beta Blocker use vs. Low HDL. The natural log of the odds ratio [ln(OR)]= 2. Using the table from question 1, the standard error of ln(OR)= 3. Using the answer for...

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1. Above is the simple crosstab for Beta Blocker use vs. Low HDL. The natural log of the odds ratio [ln(OR)]= 2. Using the table from question 1, the standard error of ln(OR)= 3. Using the answer for...

Homework Answers

Add Answer to: 1. Above is the simple crosstab for Beta Blocker use vs. Low HDL. The natural log of the odds ratio [ln(OR)]= 2. Using the table from question 1, the standard error of ln(OR)= 3. Using the answer for...

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1. Above is the simple crosstab for Beta Blocker use vs. Low HDL. The natural log of the odds ratio [ln(OR)]= 2. Using the table from question 1, the standard error of ln(OR)= 3. Using the answer for...