Why do we need either a differential amplifier or differential probes to measures voltages across two floating point using an Oscilloscope?
In precise measurement, it is essential that the measuring instrument shouldn't affect the quantity being measured.
In resistance measurement, the basic relationship R = V/I is used. In measurement of resistance, ammeter is connected in series with resistance and voltmeter across it to read these quantities. In normal measurement, two wires from resistor connect to voltage source in the meter and same wires also measure the current. Since resistance of these lead wires is usually negligible compared to that being measured, this is sufficiently accurate.
However, when the resistance is very low (which is usually the case when for resistivity measurement), the lead wire resistance is comparable to the one being measured, these wires themselves will drop considerable voltage . So the voltage being measured across unknown resistance cannot be measured properly.
To overcome this problem, two sets of wires are used. One set serves to supply current to the resistance, and second pair to measure voltage across it. This second pair (voltage probes) do not draw appreciable current, as voltmeter resistance is high. Current probe drop is not in the picture.
The reading thus obtained is quite accurate. Hence for measurement of small resistance in milli ohm and micro ohm range, always 4 terminal measurement is used.
Why do we need either a differential amplifier or differential probes to measures voltages across two floating point using an Oscilloscope?
Why do we need either a differential amplifier or differential probes to measures voltages across two floating point using an Oscilloscope?
Why do we need to assume constant viscosity for a flowing fluid system when using the equations for momentum balances, since viscosity term is already outside the partial differential sign/ function.
1. Assume we are using the simple model for floating-point representation as given in this book (the representation uses a 14-bit format, 5 bits for the exponent with a bias of 15, a normalized mantissa of 8 bits, and a single sign bit for the number): a) Show how the computer would represent the numbers 100.0 and 0.25 using this floating-point format. b) Show how the computer would add the two floating-point numbers in part a by changing one of...
1. Let a and b be two positive floating-point numbers with the same exponent. Explain why the computed difference aeb is always exact using IEEE arithmetic.
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D Question 15 5 pts How many boundary conditions do we need to specify for the following differential equation? 1эт two O four O one none O three
D Question 15 5 pts How many boundary conditions do we need to specify for the following differential equation? 1эт two O four O one none O three
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Un 100nFR out 2kC2 4.7uF Figure 3-3 (a) AC-coupled and (b) DC-coupled non-inverting AC-amplifier a) Why do you need a 100kS2 resistor to ground in the AC-coupled amplifier? b) Wharis the mainal and minima input ipedane Z- of this a ih freguencies do they occur? c) Where is the 3dB breakpoint frequency for the amplifier in Figure 3-3b? d) How large is Zin at the 3dB breakpoint frequency? e) What are the differences between the two circuits in Figure 3-3a...
Problem 2: BJT Small-Signal Voltage Amplifiers in the lectures, we covered in detail the analysis of an npn BJT amplifier that utilizes a single-supply DC biasing. In this problem, you will meet two additional amplifier architectures- one that is based on dual DC supplies combined with a DC current source, and the other that utilizes a pnp BJT with single-supply biasing. In both problems (below) you need to manually find the amplifier's Q-point (that is, the DC values of Ic...