Answer probability of getting a sum of 7 = 1/6
When two 6 sided dice or a dice are rolled the outcome is given in table :
Total no of outcomes = 36
Let E1 = event of getting a sum of 7
n(E1)= (1,6),(2,5),(3,4),(4,3),(5,2),(6,1) = 6
P(E1)= probability of getting a sum of 7
P(E1) =number of outcomes /total number of outcomes
P(E1) =6/36 =1/6
Please Explain 2. If rolling two 6-sided dice, find the probability of obtaining a sum of 7. 2. If rolling two 6-sided dice, find the probability of obtaining a sum of 7.
2. If rolling two 6-sided dice, find the probability of obtaining a sum of 7.
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