Solution:
Given that the following information
A sample of seven households was obtained, and information on their income and food expenditure for the past month was collected.
a.
b.
a.X Values
∑ = 16300
Mean = 2328.571
∑(X - Mx)2 = SSx =
4994285.714
Y Values
∑ = 4600
Mean = 657.143
∑(Y - My)2 = SSy =
237142.857
X and Y Combined
N = 7
∑(X - Mx)(Y - My) = 1008571.429
R Calculation
r = ∑((X - My)(Y - Mx)) /
√((SSx)(SSy))
r = 1008571.429 / √((4994285.714)(237142.857)) = 0.9268
Hence there is strong positive correlation
b.
Sum of X = 16300
Sum of Y = 4600
Mean X = 2328.5714
Mean Y = 657.1429
Sum of squares (SSX) = 4994285.7143
Sum of products (SP) = 1008571.4286
Regression Equation = ŷ = bX + a
b = SP/SSX =
1008571.43/4994285.71 = 0.2020
a = MY - bMX = 657.14 -
(0.2*2328.57) = 186.8993
ŷ = 0.2020X + 186.8993
c. For every increase in x, y will change to 0.2020 and this is value of slope
d. For x=5200,
ŷ = (0.2020*5200) + 186.8993=1237.2993
e.
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