Question

Q1) Torques and equilibrium Part A: use the following methods to find the center of mass for a measuring stick with a length of 1 meter 1) The edge of the table method 2) Pivot method 3) Two fingers method: average value is: 0.505 meters average value is: 0.502 meters average value is:0.503 meters Part B: Attach the supports at the 20cm mark of your meter stick. attach the 5kg at the 5cm mark.by trail and error find the mass and location of a third weight that will bring the system into equilibrium ,be sure to include the mass of any clips you may use to hold the weights. Experimental results: weight :0.2 kgposition: 0.397 meters Now mathematically show that the system is in equilibrium in two ways 1) Mass of the stick : 0.1383 kg Compute the net torque about 20 cm mark. 2) Compute the net torque about the end of the stick.

the experimental part for this question is all answered there is only the last part where it says:

1. Compute the net torque about 20 cm mark.                      Mass of the stick : 0.1383 kg

2. Compute the net torque about the end of the stick.

please be sure to put detailed answer for both parts 1 and 2

thanks for the help!

Answer 1