(1 point) Solve the wave equation with fixed endpoints and the given initial displacement and velocity. a2 ,0<x<L, t > 0 a(0. t) = 0, u(L, t) = 0, t > 0 Ou Ot ηπα t) + B,, sin (m Now we c...
1. Consider the Partial Differential Equation ot u(0,t) = u(r, t) = 0 a(x, 0)-x (Y), sin (! We know the general solution to the Basic Heat Equation is u(z,t)-Σ b e ). n= 1 (b) Find the unique solution that satisfies the given initial condition ur, 0) -2. (Hint: bn is given by the Fourier Coefficients-f(z),sin(Y- UsefulFormulas/Facts for PDEs/Fourier Series 1)2 (TiT) » x sin aL(1)1 a24(부) (TiT) 1)+1 0 1. Consider the Partial Differential Equation ot u(0,t) =...
Solve the wave equation a2 ∂2u ∂x2 = ∂2u ∂t2 , 0 < x < L, t > 0 (see (1) in Section 12.4) subject to the given conditions. u(0, t) = 0, u(L, t) = 0 u(x, 0) = 4hx L , 0 < x < L 2 4h 1 − x L , L 2 ≤ x < L , ∂u ∂t t = 0 = 0 We were unable to transcribe this imageWe were unable to transcribe...
3. Using the linearity of the wave equation, solve the wave equation problem 82u 2 82u a(0, t) = 0 u(L,t)0 u(z,0) = sin( ) (z, 0) = sin( F) 3. Using the linearity of the wave equation, solve the wave equation problem 82u 2 82u a(0, t) = 0 u(L,t)0 u(z,0) = sin( ) (z, 0) = sin( F)
Mark which statements below are true, using the following: Consider the diffusion problem au Ou u(0, t) = 0, u(L, t) = 50 u(x,0-fx where FER is a constant, forcing term. Any attempt to solve this using separation of variables fails. This is because the PDE is not homogeneous. A more fruitful approach arises from splitting the solution into the sum of two parts, taking into account that all change eventually dies out. That is there is a transient part...
츨…<L. t-o(see (1) in Section i2 4) s bject to the given conditions. Solve the wave equation, .a a r u(0, t)=0, u(T, t)=0, t> 0 ux, o) 0.01 sin(5tx), 0u t=0 u(x, t) = n=1 Need Help? LRead it . Talk to a Tutor l 츨… 0 ux, o) 0.01 sin(5tx), 0u t=0 u(x, t) = n=1 Need Help? LRead it . Talk to a Tutor l
1. Wave equation. Consider the wave equation on the finite interval (0, L) PDE BC where Neumann boundary conditions are specified Physically, with Neumann boundary conditions, u(r, t) could represent the height of a fluid that sloshes between two walls. (a) Find the general Fourier series solution by repeating the derivation from class now considering Neumann instead of Dirichlet boundary conditions. Your final solution should be (b) Consider the following general initial conditions u(x, 0)x) IC IC Derive formulas that...
9. Solve the wave problem: 0 < x < T, t> 0; Utt: t2 0; u(T, t) = 0, u(0, t) = 0, 0 SST. u(x,0) = sin(10r), u(x, 0) = sin(4æ) + 2 sin(6x), Answer: sin(10r) sin(10t). 10 sin(4r) cos(4t) + 2 sin(6x) cos(6t) + u(x, t) =
For 0 x π , 0S9, π , and 120 , solve the 2-D wave equation subject to the following conditions. u(0,y,t)-0, u(T.yt):0, u(x,0,) u(x,π, t) 0, 0 Boundary condition: C11 1 u(x),0)-sin(x)sin(2y) + sin(2x)sin(4y), 0 at It=0 Initial condition: For 0 x π , 0S9, π , and 120 , solve the 2-D wave equation subject to the following conditions. u(0,y,t)-0, u(T.yt):0, u(x,0,) u(x,π, t) 0, 0 Boundary condition: C11 1 u(x),0)-sin(x)sin(2y) + sin(2x)sin(4y), 0 at It=0 Initial condition:
6. a) For a thin conducting rod of length L = π, the temperature U(x, t) at a point 0 Sx S L at timet>0 is determined by the differential equation U, Uxx with boundary data U(x, 0) fx) and U(0,) UL, t)- 0 for all0. Show that for any positive integer k, the function U(x, t)- exp (-ak21) sin kx is a solution. It follows that Σ exp (-ak2 t) Bk sin kx is the general solution where Σ...
Now suppose f' is continuous and f" is piecewise continuous on (0, L). (b) If f(0) = f(L) = 0, then O f(x) = į bn sin ηπα L 0<x<L, n=1 612 Chapter 11 Boundary Value Problems and Fourier Expansions with bn = 2L n272 S“ r"(a)sin пах dr. L (11.3.5) Solve the initial-boundary value problem. Theorem 11.3.5 (b) will simplify the computa- tion of the coefficients in the Fourier sine series. Uit = 64uze, 0<r <3, t > 0,...