Question

17 18 19 Direction of disk rotation 14 15 19 20 21 22 23 24 Figure on the right shows the tracks and sectors on a disk. The size of File A, B, and C is 1028 bytes, 2521 bytes, and 8211 bytes respectivelv. Answer the following questions. 17 18 1 27 28/29 2212324252 If data block size is 1KB, how many data blocks does this disk contain? Answer: How many data blocks does File A take? Answe How many data blocks does File B take? Answer: How many data blocks does File C take? Answer: LOL 0

Answer 1

You didn't provide information about the size of each sector in the disk. I am considering 512 bytes as sector size. So, total capacity of your disk will be as below:

disk capacity = no. of tracks * no of sectors * sector size

= 6 * 32 * 512 = 98304 bytes = 98.304 KB $\cong$ 98 KB

data block size = 1 KB

So this disk will contain following number of data blocks:

no. of data blocks = disk_size / block_size

= 98 KB / 1 KB = 98

File A size = 1028 bytes

block size = 1 kb = 1024 bytes

no. of blocks for file A = file size / block size

= 1028 / 1024 = 1.003

So file A will take 2 blocks. In simple terms 1024 bytes will be in one block and to store other remaining 4 bytes it will take another block.

File B size = 2521

no. of blocks for file B = 2521 / 1024 = 2.46

So File B will take 3 blocks.

File C size = 8211 bytes

no. of blocks for file C = 8211 / 1024 = 8.01

So File C will take 9 blocks.