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please help and show work!

3. (a) For the car going up the incline, what percentage of the work done by the suspended weight was lost to friction? (b) F
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Answer #1

let the angle be \theta

let the distance travelled be car is = l

mass of car = m

friction coefficient = \mu

height travelled = l sin θ

friction force = LInq cos θ

so the work done by friction W_{f}=-\mu mgl\cos \theta

and work done by gravity Wg -mgl sin θ

ratio of the two will be

W.//Wg ,oot θ this is when car is going up

and

11 cot θ this is when car is going down

exact value we can'nt calculate since \mu not given

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please help and show work! 3. (a) For the car going up the incline, what percentage of the work done by the suspended weight was lost to friction? (b) For the car moving down the incline, what pe...
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