Polynomial over the Fields: a) If p(x) an element of F[x] is not irreducible, then there are at least two polynomials g(x) and h(x), neither which is a constant, such that p(x)=g(x)h(x). Explain b) U...

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Polynomial over the Fields: a) If p(x) an element of F[x] is not irreducible, then there are at least two polynomials g(x) and h(x), neither which is a constant, such that p(x)=g(x)h(x). Explain b) U...

Polynomial over the Fields:

a) If p(x) an element of F[x] is not irreducible, then there are at least two polynomials g(x) and h(x), neither which is a constant, such that p(x)=g(x)h(x). Explain

b) Use problem a to prove: If p(x) is not irreducible, then p(x)=j(x)k(x), where both j(x) and k(x) are polynomials of lower degree than p(x).

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Polynomial over the Fields: a) If p(x) an element of F[x] is not irreducible, then there are at least two polynomials g(x) and h(x), neither which is a constant, such that p(x)=g(x)h(x). Explain b) U...

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Add Answer to: Polynomial over the Fields: a) If p(x) an element of F[x] is not irreducible, then there are at least two polynomials g(x) and h(x), neither which is a constant, such that p(x)=g(x)h(x). Explain b) U...

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Polynomial over the Fields: a) If p(x) an element of F[x] is not irreducible, then there are at least two polynomials g(x) and h(x), neither which is a constant, such that p(x)=g(x)h(x). Explain b) U...